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root(3)(-128)

1283 \sqrt[3]{-128}

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Q. 1283 \sqrt[3]{-128}
  1. Identify Number and Value: Identify the number we are taking the cube root of and the value of the cube root.\newlineIn 1283\sqrt[3]{-128}, we are looking for a number which, when multiplied by itself three times, gives 128-128.
  2. Express 128-128 as Term: Express 128-128 as a term raised to the power of 33.\newline128-128 can be written as 1×128-1 \times 128, and 128128 is 22 multiplied by itself 77 times (27)(2^7).\newlineSo, 128=1×(27)-128 = -1 \times (2^7).
  3. Find Cube Root: Since we are looking for the cube root, we need to find a number that when raised to the power of 33 gives us 1×(27)-1 \times (2^7).\newlineThe cube root of 1-1 is 1-1, because (1)3=1(-1)^3 = -1.\newlineThe cube root of 272^7 is 2(7/3)2^{(7/3)} because (2(7/3))3=2(7/3×3)=27(2^{(7/3)})^3 = 2^{(7/3 \times 3)} = 2^7.
  4. Combine Cube Roots: Combine the cube roots we found in the previous step.\newlineThe cube root of 1-1 is 1-1, and the cube root of 272^7 is 27/32^{7/3}.\newlineTherefore, the cube root of 128-128 is 1×27/3-1 \times 2^{7/3}.
  5. Simplify Expression: Simplify the expression 1×273-1 \times 2^{\frac{7}{3}}. Since 73\frac{7}{3} is the same as 2+132 + \frac{1}{3}, we can express 2732^{\frac{7}{3}} as 22+132^{2 + \frac{1}{3}}. This is the same as 22×2132^2 \times 2^{\frac{1}{3}}, which is 4×4 \times cube root of 22.
  6. Calculate Final Value: Calculate the final value.\newlineThe cube root of 128-128 is 1×4×cube root of 2-1 \times 4 \times \text{cube root of } 2.\newlineSince the cube root of 22 is just 21/32^{1/3}, we can write the final answer as 4×21/3-4 \times 2^{1/3}.

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