Robert measured a line to be 2.4 inches long. If the actual length of the line is 3.2 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Robert measured a line to be 2.4 inches long. If the actual length of the line is 3.2 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand percent error: Understand the concept of percent error. Percent error is a measure of how inaccurate a measurement is, relative to the true value. The formula for percent error is: Percent Error = (|Measured Value - True Value| / True Value) × 100%Identify values: Identify the measured value and the true value. In this problem, the measured value is 2.4 inches, and the true value is 3.2 inches.Calculate absolute difference: Calculate the absolute difference between the measured value and the true value. Absolute difference = |Measured Value - True Value| = |2.4 - 3.2| = |-0.8| = 0.8 inchesCalculate percent error: Calculate the percent error using the formula. Percent Error = (Absolute difference / True Value) × 100% Percent Error = (0.8 / 3.2) × 100%Perform division and multiplication: Perform the division and multiplication to find the percent error. Percent Error = (0.8 / 3.2) × 100% = 0.25 × 100% = 25%Round percent error: Round the percent error to the nearest tenth of a percent. Since the percent error is already at a whole number, rounding to the nearest tenth of a percent does not change the value.

Robert measured a line to be $2$ . $4$ inches long. If the actual length of the line is $3$ . $2$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: _________ $\%$

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Robert measured a line to be $2$ . $4$ inches long. If the actual length of the line is $3$ . $2$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: _________ $\%$