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Riley measured a line to be 4.9 inches long. If the actual length of the line is 5 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?
Answer: 
%

Riley measured a line to be 44.99 inches long. If the actual length of the line is 55 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: _________% \%

Full solution

Q. Riley measured a line to be 44.99 inches long. If the actual length of the line is 55 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: _________% \%
  1. Understand Percent Error: Understand the concept of percent error. Percent error is a measure of how inaccurate a measurement is, compared to the true value. The formula for percent error is: Percent Error = (Measured ValueTrue Value/True Value)×100%(|\text{Measured Value} - \text{True Value}| / \text{True Value}) \times 100\%
  2. Identify Values: Identify the measured value and the true value.\newlineIn this problem, the measured value is 4.94.9 inches and the true value is 55 inches.
  3. Calculate Absolute Difference: Calculate the absolute difference between the measured value and the true value.\newlineAbsolute difference = Measured ValueTrue Value=4.95=0.1|\text{Measured Value} - \text{True Value}| = |4.9 - 5| = 0.1 inches
  4. Calculate Percent Error: Calculate the percent error using the formula.\newlinePercent Error = (Absolute difference/True Value)×100%(\text{Absolute difference} / \text{True Value}) \times 100\%\newlinePercent Error = (0.1/5)×100%(0.1 / 5) \times 100\%
  5. Perform Calculation: Perform the calculation to find the percent error. Percent Error = (0.15)×100%=0.02×100%=2%(\frac{0.1}{5}) \times 100\% = 0.02 \times 100\% = 2\%
  6. Round Percent Error: Round the percent error to the nearest tenth of a percent. Since the percent error is already at a whole number, rounding to the nearest tenth of a percent does not change the value.

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