Right triangle trigonometry: advancedep 1910 ftA room has the shape of a rectangle with a right triangle taken from one of its corners as shown. The rectangle has a length of 22 feet ( ft ) and a width of 19 ft . Both sides next to the removed corner have a length of 10 ft . What is the perimeter of the room in feet?70
Q. Right triangle trigonometry: advancedep 1910 ftA room has the shape of a rectangle with a right triangle taken from one of its corners as shown. The rectangle has a length of 22 feet ( ft ) and a width of 19 ft . Both sides next to the removed corner have a length of 10 ft . What is the perimeter of the room in feet?70
Find Hypotenuse Length: First, find the length of the hypotenuse of the right triangle using the Pythagorean theorem. a=10 ft, b=10 ft c2=a2+b2 c2=102+102 c2=100+100 c2=200 c=200 c=102 ft
Calculate Perimeter: Calculate the perimeter of the room by adding the lengths of all sides. Perimeter = 22 ft (length)+19 ft (width)+22 ft (length)+19 ft (width)−10 ft (side of triangle)−10 ft (side of triangle)+102 ft (hypotenuse) Perimeter = 22+19+22+19−10−10+102 Perimeter = 62+102 ft
Approximate Hypotenuse Value: Approximate the value of 102 to simplify the final answer. 102≈10×1.414≈14.14 ft Perimeter ≈62+14.14 Perimeter ≈76.14 ft
More problems from Pythagorean Theorem and its converse