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Rewrite the expression in the form 
k*z^(n).
Write the exponent as an integer, fraction, or an exact decimal (not a mixed number).

(10root(3)(z))/(2z^(2))=◻

Rewrite the expression in the form kzn k \cdot z^{n} .\newlineWrite the exponent as an integer, fraction, or an exact decimal (not a mixed number).\newline10z32z2= \frac{10 \sqrt[3]{z}}{2 z^{2}}=\square

Full solution

Q. Rewrite the expression in the form kzn k \cdot z^{n} .\newlineWrite the exponent as an integer, fraction, or an exact decimal (not a mixed number).\newline10z32z2= \frac{10 \sqrt[3]{z}}{2 z^{2}}=\square
  1. Given expression: We are given the expression (10z3)/(2z2)(10\sqrt[3]{z})/(2z^{2}). We need to rewrite this expression in the form kznk*z^{n}.\newlineFirst, let's express the cube root of zz as zz raised to the power of 1/31/3.\newlineExpression: (10z1/3)/(2z2)(10*z^{1/3})/(2z^{2})
  2. Expressing cube root of zz: Now, we simplify the coefficients (numerical parts) of the expression by dividing 1010 by 22.\newline10/2=510 / 2 = 5\newlineSo the expression becomes 5z1/3/z25 \cdot z^{1/3} / z^{2}.
  3. Simplifying coefficients: Next, we apply the laws of exponents to combine the zz terms. When dividing like bases, we subtract the exponents.z13z2=z132\frac{z^{\frac{1}{3}}}{z^{2}} = z^{\frac{1}{3} - 2}
  4. Combining z terms: We need to express 22 as a fraction with the same denominator as 13\frac{1}{3} to subtract the exponents easily.\newline22 can be written as 63\frac{6}{3}.\newlineSo, z132z^{\frac{1}{3} - 2} becomes z1363z^{\frac{1}{3} - \frac{6}{3}}.
  5. Expressing 22 as a fraction: Now, subtract the exponents.\newline1363=53\frac{1}{3} - \frac{6}{3} = -\frac{5}{3}\newlineSo, z1363=z53z^{\frac{1}{3} - \frac{6}{3}} = z^{-\frac{5}{3}}.
  6. Subtracting exponents: The final expression is now in the form kznk*z^{n}, where kk is 55 and nn is 53-\frac{5}{3}. So, (10z3)/(2z2)=5z53(10\sqrt[3]{z})/(2z^{2}) = 5*z^{-\frac{5}{3}}.

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