Q. Rewrite the expression as a product of four linear factors:(x2+x)2−18(x2+x)+72Answer:
Recognize Structure: Recognize the structure of the given expression.The given expression is a quadratic in form of (x2+x)2−18(x2+x)+72, which resembles the structure of (a+b)2−18(a+b)+72, where a=x2 and b=x.
Factor Quadratic Expression: Factor the quadratic expression.We can treat (x2+x) as a single variable, let's call it 'y'. So the expression becomes y2−18y+72. Now we need to factor this quadratic expression.
Find Factors of 72: Find the factors of 72 that add up to 18.The factors of 72 that add up to 18 are 6 and 12. So we can write the quadratic expression as (y−6)(y−12).
Substitute Back: Substitute back x2+x for y. Now we substitute back x2+x for y to get ((x2+x)−6)((x2+x)−12).
Expand Factors: Expand each factor to find the linear factors.We need to factor (x2+x−6) and (x2+x−12) further to find the linear factors. Let's start with (x2+x−6).
Factor x2+x−6: Factor (x2+x−6). The factors of −6 that add up to 1 (the coefficient of x) are 3 and −2. So we can write (x2+x−6) as (x+3)(x−2).
Factor x2+x−12: Factor (x2+x−12). The factors of −12 that add up to 1 (the coefficient of x) are 4 and −3. So we can write (x2+x−12) as (x+4)(x−3).
Combine Linear Factors: Combine all the linear factors.Now we have all the linear factors: (x+3), (x−2), (x+4), and (x−3). So the expression as a product of four linear factors is (x+3)(x−2)(x+4)(x−3).
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