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Rewrite the expression as a product of four linear factors:

(8x^(2)+9x)^(2)-13(8x^(2)+9x)-14
Answer:

Rewrite the expression as a product of four linear factors:\newline(8x2+9x)213(8x2+9x)14 \left(8 x^{2}+9 x\right)^{2}-13\left(8 x^{2}+9 x\right)-14 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(8x2+9x)213(8x2+9x)14 \left(8 x^{2}+9 x\right)^{2}-13\left(8 x^{2}+9 x\right)-14 \newlineAnswer:
  1. Recognize Quadratic Form: Recognize the given expression as a quadratic in form. The expression (8x2+9x)213(8x2+9x)14(8x^{2}+9x)^{2}-13(8x^{2}+9x)-14 resembles a quadratic equation in the form of (ax2+bx+c)(ax^2 + bx + c), where the variable xx is replaced by (8x2+9x)(8x^2 + 9x).
  2. Substitute and Simplify: Let y=(8x2+9x)y = (8x^2 + 9x). Substitute yy for (8x2+9x)(8x^2 + 9x) to simplify the expression. We get y213y14y^2 - 13y - 14.
  3. Factor Quadratic Equation: Factor the quadratic equation y213y14y^2 - 13y - 14. We look for two numbers that multiply to 14-14 and add up to 13-13. These numbers are 14-14 and 11. So, y213y14=(y14)(y+1)y^2 - 13y - 14 = (y - 14)(y + 1).
  4. Substitute Back and Expand: Substitute back (8x2+9x)(8x^2 + 9x) for yy. Replace yy with (8x2+9x)(8x^2 + 9x) in the factored form. We get (8x2+9x14)(8x2+9x+1)(8x^2 + 9x - 14)(8x^2 + 9x + 1).
  5. Factor Further: Factor each quadratic expression further.\newlineWe need to factor (8x2+9x14)(8x^2 + 9x - 14) and (8x2+9x+1)(8x^2 + 9x + 1) into two linear factors each.
  6. Factor 8x2+9x148x^2 + 9x - 14: Factor 8x2+9x148x^2 + 9x - 14. We look for two numbers that multiply to 8(14)=1128*(-14) = -112 and add up to 99. These numbers are 1616 and 7-7. We can write 9x9x as 16x7x16x - 7x, so the expression becomes 8x2+16x7x148x^2 + 16x - 7x - 14. Now, factor by grouping: (8x2+16x)(7x+14)=8x(x+2)7(x+2)(8x^2 + 16x) - (7x + 14) = 8x(x + 2) - 7(x + 2). Finally, we get 8x2+9x148x^2 + 9x - 1400.
  7. Factor 8x2+9x+18x^2 + 9x + 1: Factor 8x2+9x+18x^2 + 9x + 1. This expression is a bit trickier because the factors of 88 and 11 are not as straightforward. However, we can still attempt to factor by trial and error or by using the quadratic formula. Upon inspection, it seems that this expression does not factor nicely into linear factors with integer coefficients. This is a math error because we assumed it could be factored into linear factors, but it cannot.

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