Reduce to simplest form. -(3)/(5)+(1)/(3)=

Find Common Denominator: Find a common denominator for the fractions -3/5 and 1/3. The common denominator for 5 and 3 is 15, so we will convert both fractions to have a denominator of 15.Convert to Denominator 15: Convert each fraction to an equivalent fraction with a denominator of 15. For -3/5, we multiply the numerator and denominator by 3 to get -9/15. For 1/3, we multiply the numerator and denominator by 5 to get 5/15.Add Fractions: Add the two fractions with the common denominator. -9/15 + 5/15 = (-9 + 5)/15Perform Addition: Perform the addition in the numerator. -9 + 5 = -4 So, the combined fraction is -4/15.Check for Simplification: Check if the fraction can be simplified further. The fraction -4/15 cannot be simplified further because 4 and 15 have no common factors other than 1.

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Reduce to simplest form.

-(3)/(5)+(1)/(3)=

Reduce to simplest form. $\newline$ $-\frac{3}{5}+\frac{1}{3}=$

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Grade 6

Multiply using the distributive property

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Q. Reduce to simplest form.

\newline

-\frac{3}{5}+\frac{1}{3}=

Find Common Denominator: Find a common denominator for the fractions $-\frac{3}{5}$ and $\frac{1}{3}$ . The common denominator for $5$ and $3$ is $15$ , so we will convert both fractions to have a denominator of $15$ .
Convert to Denominator $15$ : Convert each fraction to an equivalent fraction with a denominator of $15$ . For $-\frac{3}{5}$ , we multiply the numerator and denominator by $3$ to get $-\frac{9}{15}$ . For $\frac{1}{3}$ , we multiply the numerator and denominator by $5$ to get $\frac{5}{15}$ .
Add Fractions: Add the two fractions with the common denominator. $\newline$ $-\frac{9}{15} + \frac{5}{15} = \frac{-9 + 5}{15}$
Perform Addition: Perform the addition in the numerator. $\newline$ $-9 + 5 = -4$ $\newline$ So, the combined fraction is $-\frac{4}{15}$ .
Check for Simplification: Check if the fraction can be simplified further. $\newline$ The fraction $-\frac{4}{15}$ cannot be simplified further because $4$ and $15$ have no common factors other than $1$ .