Reduce to simplest form. (3)/(2)+(-(6)/(5))=

Identify LCD: Identify the least common denominator (LCD) for the fractions (3/2) and (-(6/5)). The denominators are 2 and 5, so the LCD is 2 × 5 = 10.Convert to LCD: Convert each fraction to an equivalent fraction with the LCD as the denominator. For (3/2), multiply both the numerator and the denominator by 5 to get (3 × 5)/(2 × 5) = 15/10. For (-(6/5)), multiply both the numerator and the denominator by 2 to get (-(6 × 2))/(5 × 2) = -12/10.Add with LCD: Add the fractions with the common denominator. (15/10) + (-12/10) = (15 - 12)/10 = 3/10.Check for Simplification: Check if the resulting fraction can be simplified further. The fraction 3/10 is already in its simplest form because 3 and 10 have no common factors other than 1.

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Math Problems

Grade 6

Multiply using the distributive property

Full solution

Q. Reduce to simplest form.

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\frac{3}{2}+\left(-\frac{6}{5}\right)=

Identify LCD: Identify the least common denominator (LCD) for the fractions $(\frac{3}{2})$ and $(\frac{-6}{5})$ . The denominators are $2$ and $5$ , so the LCD is $2 \times 5 = 10$ .
Convert to LCD: Convert each fraction to an equivalent fraction with the LCD as the denominator. $\newline$ For $(\frac{3}{2})$ , multiply both the numerator and the denominator by $5$ to get $(\frac{3 \times 5}{2 \times 5}) = \frac{15}{10}$ . $\newline$ For $(\frac{-6}{5})$ , multiply both the numerator and the denominator by $2$ to get $(\frac{-(6 \times 2)}{5 \times 2}) = \frac{-12}{10}$ .
Add with LCD: Add the fractions with the common denominator. $\newline$ $(\frac{15}{10}) + (\frac{-12}{10}) = \frac{15 - 12}{10} = \frac{3}{10}$ .
Check for Simplification: Check if the resulting fraction can be simplified further. $\newline$ The fraction $\frac{3}{10}$ is already in its simplest form because $3$ and $10$ have no common factors other than $1$ .