Reduce to simplest form. (12)/(11)-(-(2)/(3))=

Identify Terms: Identify the terms to be subtracted and rewrite the subtraction of a negative as addition. (12/11) - (-(2/3)) can be rewritten as (12/11) + (2/3) because subtracting a negative is the same as adding a positive.Find Common Denominator: Find a common denominator for the fractions to combine them. The least common denominator (LCD) for 11 and 3 is 33.Convert Fractions: Convert each fraction to an equivalent fraction with the LCD as the denominator. (12/11) becomes (12*3)/(11*3) = (36/33) and (2/3) becomes (2*11)/(3*11) = (22/33).Add Fractions: Add the fractions with the common denominator. (36/33) + (22/33) = (36 + 22)/33 = (58/33).Check Simplification: Check if the resulting fraction can be simplified. The fraction (58/33) is already in its simplest form because 58 and 33 have no common factors other than 1.

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Math Problems

Grade 6

Multiply using the distributive property

Full solution

Q. Reduce to simplest form.

\newline

\frac{12}{11}-\left(-\frac{2}{3}\right)=

Identify Terms: Identify the terms to be subtracted and rewrite the subtraction of a negative as addition. $\newline$ $(12/11) - (-(2/3))$ can be rewritten as $(12/11) + (2/3)$ because subtracting a negative is the same as adding a positive.
Find Common Denominator: Find a common denominator for the fractions to combine them. $\newline$ The least common denominator (LCD) for $11$ and $3$ is $33$ .
Convert Fractions: Convert each fraction to an equivalent fraction with the LCD as the denominator. $\newline$ $(\frac{12}{11})$ becomes $(\frac{12\times3}{11\times3}) = (\frac{36}{33})$ and $(\frac{2}{3})$ becomes $(\frac{2\times11}{3\times11}) = (\frac{22}{33})$ .
Add Fractions: Add the fractions with the common denominator. $\newline$ $(\frac{36}{33}) + (\frac{22}{33}) = \frac{36 + 22}{33} = (\frac{58}{33})$ .
Check Simplification: Check if the resulting fraction can be simplified. $\newline$ The fraction $(\frac{58}{33})$ is already in its simplest form because $58$ and $33$ have no common factors other than $1$ .