Re-write the quadratic function below in Standard Form y=6(x+4)^(2)+2 Answer: y=

Expand Binomial: Expand the squared binomial. We need to expand the expression $ (x+4)^2 $ by using the binomial square formula $ (a+b)^2 = a^2 + 2ab + b^2 $. Let's calculate $ (x+4)^2 $: $ (x+4)^2 = x^2 + 2 \cdot x \cdot 4 + 4^2 $ $ (x+4)^2 = x^2 + 8x + 16 $Multiply by Coefficient: Multiply the expanded binomial by the coefficient 6. Now we multiply each term of the expanded binomial by 6: $ 6(x^2 + 8x + 16) = 6 \cdot x^2 + 6 \cdot 8x + 6 \cdot 16 $ $ 6(x^2 + 8x + 16) = 6x^2 + 48x + 96 $Add Constant Term: Add the constant term to the expression. Finally, we add the constant term 2 to the expression obtained in Step 2: $ y = 6x^2 + 48x + 96 + 2 $ $ y = 6x^2 + 48x + 98 $

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Re-write the quadratic function below in Standard Form

y=6(x+4)^(2)+2
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=6(x+4)^{2}+2$ $\newline$ Answer: $y=$

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Algebra 2

Write a quadratic function from its zeros

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Q. Re-write the quadratic function below in Standard Form

\newline

y=6(x+4)^{2}+2

\newline

Answer:

y=

Expand Binomial: Expand the squared binomial. $\newline$ We need to expand the expression $(x+4)^2$ by using the binomial square formula $(a+b)^2 = a^2 + 2ab + b^2$ . $\newline$ Let's calculate $(x+4)^2$ : $\newline$ $(x+4)^2 = x^2 + 2 \cdot x \cdot 4 + 4^2$ $\newline$ $(x+4)^2 = x^2 + 8x + 16$
Multiply by Coefficient: Multiply the expanded binomial by the coefficient $6$ . $\newline$ Now we multiply each term of the expanded binomial by $6$ : $\newline$ $6(x^2 + 8x + 16) = 6 \cdot x^2 + 6 \cdot 8x + 6 \cdot 16$ $\newline$ $6(x^2 + 8x + 16) = 6x^2 + 48x + 96$
Add Constant Term: Add the constant term to the expression. $\newline$ Finally, we add the constant term $2$ to the expression obtained in Step $2$ : $\newline$ $y = 6x^2 + 48x + 96 + 2$ $\newline$ $y = 6x^2 + 48x + 98$