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r=(-181 k(T_(t)-T_(w)))/(200)
The formula gives the temperature change 
r, in degrees Celsius per minute, of tortellini while it is being cooked, given the initial temperatures of the tortellini, 
T_(t), and the water, 
T_(w), in degrees Celsius, and a heat conductivity of the tortellini of 
k joules per square centimeter per second. Which equation correctly gives the heat conductivity of the tortellini in terms of the temperature change per minute and the initial temperatures of the water and tortellini?
Choose 1 answer:
(A) 
k=(200(r+T_(w)))/(-181T_(t))
(B) 
k=(200 r)/(-181(T_(t)-T_(w)))
(C) 
k=(200 r+T_(W))/(-181T_(t))

The formula gives the temperature change rr, in degrees Celsius per minute, of tortellini while it is being cooked, given the initial temperatures of the tortellini, TtT_{t}, and the water, TwT_{w}, in degrees Celsius, and a heat conductivity of the tortellini of kk joules per square centimeter per second. Which equation correctly gives the heat conductivity of the tortellini in terms of the temperature change per minute and the initial temperatures of the water and tortellini?\newlineChoose 11 answer:\newline(A) k=200(r+Tw)181Ttk=\frac{200(r+T_{w})}{-181T_{t}}\newline(B) k=200r181(TtTw)k=\frac{200r}{-181(T_{t}-T_{w})}\newline(C) k=200r+TW181Ttk=\frac{200r+T_{W}}{-181T_{t}}

Full solution

Q. The formula gives the temperature change rr, in degrees Celsius per minute, of tortellini while it is being cooked, given the initial temperatures of the tortellini, TtT_{t}, and the water, TwT_{w}, in degrees Celsius, and a heat conductivity of the tortellini of kk joules per square centimeter per second. Which equation correctly gives the heat conductivity of the tortellini in terms of the temperature change per minute and the initial temperatures of the water and tortellini?\newlineChoose 11 answer:\newline(A) k=200(r+Tw)181Ttk=\frac{200(r+T_{w})}{-181T_{t}}\newline(B) k=200r181(TtTw)k=\frac{200r}{-181(T_{t}-T_{w})}\newline(C) k=200r+TW181Ttk=\frac{200r+T_{W}}{-181T_{t}}
  1. Given Formula Manipulation: The given formula is r=181k(TtTw)200r=\frac{-181 k(T_{t}-T_{w})}{200}. We need to solve for kk.
  2. Multiply by 200200: First, multiply both sides of the equation by 200200 to get rid of the denominator:\newline200r=181k(TtTw)200r = -181k(T_{t} - T_{w})
  3. Divide by 181(TtTw)-181(T_{t} - T_{w}): Next, divide both sides of the equation by 181(TtTw)-181(T_{t} - T_{w}) to solve for kk:k=200r181(TtTw)k = \frac{200r}{-181(T_{t} - T_{w})}
  4. Check Answer Choices: Check the answer choices to see which one matches the derived equation for kk. The correct equation is:\newlinek=200r181(T(t)T(w))k = \frac{200r}{-181(T_{(t)} - T_{(w)})}
  5. Match with Option (B): Comparing the derived equation with the answer choices, we find that option (B) matches:\newline(B) k=200r181(TtTw)k = \frac{200r}{-181(T_{t} - T_{w})}

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