QuestionGiven tanA=−6011 and that angle A is in Quadrant IV, find the exact value of cscA in simplest radical form using a rational denominator.Answer Attempt 1 out of 2
Q. QuestionGiven tanA=−6011 and that angle A is in Quadrant IV, find the exact value of cscA in simplest radical form using a rational denominator.Answer Attempt 1 out of 2
Recall Tangent Definition: Recall the definition of the tangent function in terms of sine and cosine: tanA=cosAsinA. Since tanA is negative in Quadrant IV and cosine is positive in Quadrant IV, sine must be negative. We also know that sin2A+cos2A=1, which is the Pythagorean identity.
Representing sin and cos: Given tanA=−6011, we can represent sinA and cosA as sinA=−k11 and cosA=k60, where k is the hypotenuse of the right triangle formed by the angle A. We need to find the value of k using the Pythagorean identity.
Finding Value of k: Using the Pythagorean identity sin2A+cos2A=1, we substitute the values of sinA and cosA to find k: (−k11)2+(k60)2=1k2121+k23600=1k23721=1k2=3721k=3721k=61, since k is the hypotenuse and must be positive.
Calculating csc A: Now that we have k, we can find sinA=−k11=−6111. The cosecant function is the reciprocal of the sine function, so cscA=sinA1.
Calculating cscA: Now that we have k, we can find sinA=−k11=−6111. The cosecant function is the reciprocal of the sine function, so cscA=sinA1.Calculate cscA using the value of sinA:cscA=(−6111)1cscA=−1161Since we are looking for the exact value in simplest radical form with a rational denominator, we need to check if the sine value can be expressed in radical form. However, since −6111 is already in simplest form and does not involve a radical, this is the final answer.
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