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Question 3
Solve the equation 
(x)/(x-1)+(2)/(5)=(3)/(2)

Question 33\newlineSolve the equation xx1+25=32 \frac{x}{x-1}+\frac{2}{5}=\frac{3}{2}

Full solution

Q. Question 33\newlineSolve the equation xx1+25=32 \frac{x}{x-1}+\frac{2}{5}=\frac{3}{2}
  1. Find Common Denominator: To solve the equation (x)/(x1)+(2)/(5)=(3)/(2)(x)/(x-1) + (2)/(5) = (3)/(2), we need to find a common denominator for the fractions on the left side of the equation. The common denominator for (x1)(x-1) and 55 is 5(x1)5(x-1).
  2. Eliminate Fractions: Multiply each term by the common denominator 5(x1)5(x-1) to eliminate the fractions:\newline5(x1)×x(x1)+5(x1)×25=5(x1)×325(x-1) \times \frac{x}{(x-1)} + 5(x-1) \times \frac{2}{5} = 5(x-1) \times \frac{3}{2}.
  3. Simplify Terms: Simplify each term: 5x+2(x1)=(32)5(x1)5x + 2(x-1) = \left(\frac{3}{2}\right) \cdot 5(x-1).
  4. Combine Like Terms: Distribute the 22 and the (3/2)×5(3/2) \times 5 across the respective parentheses:\newline5x+2x2=(152)(x1)5x + 2x - 2 = (\frac{15}{2})(x-1).
  5. Distribute Right Side: Combine like terms on the left side of the equation: 7x2=(152)(x1)7x - 2 = \left(\frac{15}{2}\right)(x-1).
  6. Clear Fractions: Distribute the 152\frac{15}{2} on the right side of the equation: 7x2=152x1527x - 2 = \frac{15}{2}x - \frac{15}{2}.
  7. Simplify Equation: Multiply every term by 22 to clear the fraction on the right side of the equation:\newline2(7x)2(2)=2(152x)2(152)2(7x) - 2(2) = 2\left(\frac{15}{2}x\right) - 2\left(\frac{15}{2}\right).
  8. Isolate Variable: Simplify the equation: 14x4=15x1514x - 4 = 15x - 15.
  9. Solve for x: Subtract 14x14x from both sides to get the x terms on one side:\newline4=x15-4 = x - 15.
  10. Solve for x: Subtract 14x14x from both sides to get the x terms on one side:\newline4=x15-4 = x - 15. Add 1515 to both sides to solve for x:\newlinex=11x = 11.

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