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y=-3(x-2)^(2)+12 Vertex: ◻

y=−3(x−2)2+12 y=-3(x-2)^{2}+12 \newlineVertex: □ \square

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Solve for a variable using properties of multiplicationright chevron icon

Full solution

Q. y=−3(x−2)2+12 y=-3(x-2)^{2}+12 \newlineVertex: □ \square
  1. Vertex Form Definition: The vertex form of a parabola's equation is y=a(x−h)2+ky=a(x-h)^2+k, where (h,k)(h,k) is the vertex of the parabola.
  2. Identifying Vertex Form: In the given equation y=−3(x−2)2+12y=-3(x-2)^2+12, we can see that it is already in vertex form. Thus, we can directly read off the vertex (h,k)(h,k) from the equation.
  3. Determining Vertex Coordinates: Comparing the given equation with the vertex form, we have h=2h=2 and k=12k=12. Therefore, the vertex of the parabola is (2,12)(2,12).

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