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Amir stands on a balcony and throws a ball to his dog, who is at ground level.
The ball's height (in meters above the ground), x seconds after Amir threw it, is modeled by:
h(x)=-(x-2)^(2)+16
What is the height of the ball at the time it is thrown?
◻ meters

Amir stands on a balcony and throws a ball to his dog, who is at ground level.\newlineThe ball's height (in meters above the ground), x x seconds after Amir threw it, is modeled by:\newlineh(x)=(x2)2+16 h(x)=-(x-2)^{2}+16 \newlineWhat is the height of the ball at the time it is thrown?\newline \square meters

Full solution

Q. Amir stands on a balcony and throws a ball to his dog, who is at ground level.\newlineThe ball's height (in meters above the ground), x x seconds after Amir threw it, is modeled by:\newlineh(x)=(x2)2+16 h(x)=-(x-2)^{2}+16 \newlineWhat is the height of the ball at the time it is thrown?\newline \square meters
  1. Identify Time of Throw: Identify the time when the ball is thrown.\newlineThe time when the ball is thrown is at the beginning of the trajectory, which is at x=0x = 0 seconds.
  2. Substitute x=0x = 0: Substitute x=0x = 0 into the height function to find the height at the time the ball is thrown.\newlineh(x)=(x2)2+16h(x) = -(x - 2)^2 + 16\newlineh(0)=((0)2)2+16h(0) = -((0) - 2)^2 + 16
  3. Calculate Height: Calculate the height using the given function.\newlineh(0)=(02)2+16h(0) = -(0 - 2)^2 + 16\newlineh(0)=(2)2+16h(0) = -(-2)^2 + 16\newlineh(0)=(4)+16h(0) = -(4) + 16\newlineh(0)=164h(0) = 16 - 4\newlineh(0)=12h(0) = 12

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