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If a store sold a toy set at $80, it would make a profit of $2700. If each toy set is sold at 
$40 instead, the shop will make a loss of $900. How many toy sets are there? What is the cost price of each toy sets?

If a store sold a toy set at $80 \$ 80 , it would make a profit of $2700 \$ 2700 . If each toy set is sold at $40 \$ 40 instead, the shop will make a loss of $900 \$ 900 . How many toy sets are there? What is the cost price of each toy sets?

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Q. If a store sold a toy set at $80 \$ 80 , it would make a profit of $2700 \$ 2700 . If each toy set is sold at $40 \$ 40 instead, the shop will make a loss of $900 \$ 900 . How many toy sets are there? What is the cost price of each toy sets?
  1. Define Variables: Let's denote the number of toy sets as nn and the cost price of each toy set as CPCP. When the store sells each toy set at $80\$80, it makes a profit of $2700\$2700. The profit can be calculated by the formula: Profit = Selling Price (SP) - Cost Price (CP). So, we have the equation:\newlinen×$80n×CP=$2700n \times \$80 - n \times CP = \$2700
  2. Calculate Profit Equation: Now, when the store sells each toy set at $40\$40, it incurs a loss of $900\$900. The loss can be calculated by the formula: Loss = Cost Price (CP) - Selling Price (SP). So, we have the equation:\newlinen×CPn×$40=$900n \times CP - n \times \$40 = \$900
  3. Calculate Loss Equation: We have two equations now:\newline11) n×($80)n×CP=($2700)n \times (\$80) - n \times CP = (\$2700)\newline22) n×CPn×($40)=($900)n \times CP - n \times (\$40) = (\$900)\newlineLet's simplify both equations by factoring out 'n':\newline11) ($80nCPn=$2700)(\$80n - CPn = \$2700)\newline22) (CPn$40n=$900)(CPn - \$40n = \$900)
  4. Simplify Equations: We can add these two equations to eliminate 'CPn':\newline($80nCPn)+(CPn$40n)=$2700+$900(\$80n - CPn) + (CPn - \$40n) = \$2700 + \$900\newlineThis simplifies to:\newline$80n$40n=$3600\$80n - \$40n = \$3600
  5. Eliminate CPn: Now, we solve for 'n':\newline40n=360040n = 3600\newlinen = 360040\frac{3600}{40}\newlinen = 9090\newlineSo, there are 9090 toy sets.
  6. Solve for n: Now that we know nn, we can substitute it back into either equation to find CPCP. Let's use the first equation:\newline$80nCPn=$2700\$80n - CPn = \$2700\newline$80×90CP×90=$2700\$80 \times 90 - CP \times 90 = \$2700\newline720090CP=$27007200 - 90CP = \$2700
  7. Substitute nn into Equation: Now, we solve for 'CPCP':\newline72002700=90CP7200 - 2700 = 90CP\newline4500=90CP4500 = 90CP\newlineCP=450090CP = \frac{4500}{90}\newlineCP=$(50)CP = \$(50)\newlineSo, the cost price of each toy set is \$(\(50\)).

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