If a store sold a toy set at $80, it would make a profit of $2700. If each toy set is sold at $40 instead, the shop will make a loss of $900. How many toy sets are there? What is the cost price of each toy sets?
Q. If a store sold a toy set at $80, it would make a profit of $2700. If each toy set is sold at $40 instead, the shop will make a loss of $900. How many toy sets are there? What is the cost price of each toy sets?
Define Variables: Let's denote the number of toy sets as n and the cost price of each toy set as CP. When the store sells each toy set at $80, it makes a profit of $2700. The profit can be calculated by the formula: Profit = Selling Price (SP) - Cost Price (CP). So, we have the equation:n×$80−n×CP=$2700
Calculate Profit Equation: Now, when the store sells each toy set at $40, it incurs a loss of $900. The loss can be calculated by the formula: Loss = Cost Price (CP) - Selling Price (SP). So, we have the equation:n×CP−n×$40=$900
Calculate Loss Equation: We have two equations now:1) n×($80)−n×CP=($2700)2) n×CP−n×($40)=($900)Let's simplify both equations by factoring out 'n':1) ($80n−CPn=$2700)2) (CPn−$40n=$900)
Simplify Equations: We can add these two equations to eliminate 'CPn':($80n−CPn)+(CPn−$40n)=$2700+$900This simplifies to:$80n−$40n=$3600
Eliminate CPn: Now, we solve for 'n':40n=3600n = 403600n = 90So, there are 90 toy sets.
Solve for n: Now that we know n, we can substitute it back into either equation to find CP. Let's use the first equation:$80n−CPn=$2700$80×90−CP×90=$27007200−90CP=$2700
Substitute n into Equation: Now, we solve for 'CP':7200−2700=90CP4500=90CPCP=904500CP=$(50)So, the cost price of each toy set is \$(\(50\)).