Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Prove the identity.

(cot^(2)x)/(csc x+1)=csc x-1
Note that each Statement must be based on a Rule chosen from the Rule menu. To se the right of the Rule.
Statement

Prove the identity.\newlinecot2xcscx+1=cscx1 \frac{\cot ^{2} x}{\csc x+1}=\csc x-1 \newlineNote that each Statement must be based on a Rule chosen from the Rule menu. To se the right of the Rule.\newlineStatement

Full solution

Q. Prove the identity.\newlinecot2xcscx+1=cscx1 \frac{\cot ^{2} x}{\csc x+1}=\csc x-1 \newlineNote that each Statement must be based on a Rule chosen from the Rule menu. To se the right of the Rule.\newlineStatement
  1. Start with left-hand side: We start with the left-hand side of the identity and try to transform it into the right-hand side.\newlineWe have: cot2xcscx+1\frac{\cot^{2}x}{\csc x+1}\newlineRecall the trigonometric identities: cot(x)=1tan(x)\cot(x) = \frac{1}{\tan(x)} and csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}
  2. Rewrite cot(x)\cot(x): Rewrite cot(x)\cot(x) in terms of sin(x)\sin(x) and cos(x)\cos(x): cot(x)=cos(x)sin(x)\cot(x) = \frac{\cos(x)}{\sin(x)}\newlineSo, cot2(x)=(cos(x)sin(x))2\cot^2(x) = \left(\frac{\cos(x)}{\sin(x)}\right)^2
  3. Rewrite left-hand side: Now, let's rewrite the left-hand side using the cot(x)\cot(x) in terms of sin(x)\sin(x) and cos(x)\cos(x):cot2xcscx+1=(cos(x)sin(x))21sin(x)+1\frac{\cot^{2}x}{\csc x+1} = \frac{(\frac{\cos(x)}{\sin(x)})^2}{\frac{1}{\sin(x)} + 1}
  4. Multiply by sin(x)\sin(x): Multiply both numerator and denominator by sin(x)\sin(x) to get rid of the fraction in the denominator:\newline(cos(x)sin(x))2sin(x)(1sin(x)+1)sin(x)\left(\frac{\cos(x)}{\sin(x)}\right)^2 \cdot \frac{\sin(x)}{\left(\frac{1}{\sin(x)} + 1\right) \cdot \sin(x)}\newline=cos2(x)sin2(x)sin(x)1+sin(x)= \frac{\cos^2(x)}{\sin^2(x)} \cdot \frac{\sin(x)}{1 + \sin(x)}
  5. Simplify expression: Simplify the expression by canceling out a sin(x)\sin(x) in the numerator and denominator: cos2(x)sin(x)÷(1+sin(x))\frac{\cos^2(x)}{\sin(x)} \div (1 + \sin(x)) = cos2(x)sin(x)(1+sin(x))\frac{\cos^2(x)}{\sin(x) \cdot (1 + \sin(x))}
  6. Use Pythagorean identity: Use the Pythagorean identity: sin2(x)+cos2(x)=1\sin^2(x) + \cos^2(x) = 1 So, cos2(x)=1sin2(x)\cos^2(x) = 1 - \sin^2(x) Replace cos2(x)\cos^2(x) in the expression: (1sin2(x))/(sin(x)(1+sin(x)))(1 - \sin^2(x)) / (\sin(x) \cdot (1 + \sin(x)))
  7. Factor numerator: Factor the numerator as a difference of squares: (1sin(x))(1+sin(x))sin(x)(1+sin(x))\frac{(1 - \sin(x)) \cdot (1 + \sin(x))}{\sin(x) \cdot (1 + \sin(x))}
  8. Cancel common factor: Cancel out the common factor (1+sin(x))(1 + \sin(x)) in the numerator and denominator:\newline1sin(x)sin(x)\frac{1 - \sin(x)}{\sin(x)}
  9. Rewrite 1sin(x)\frac{1}{\sin(x)}: Rewrite 1sin(x)\frac{1}{\sin(x)} as csc(x)\csc(x):\newlinecsc(x)sin(x)sin(x)\csc(x) - \frac{\sin(x)}{\sin(x)}\newline= csc(x)1\csc(x) - 1
  10. Transform into right-hand side: We have now transformed the left-hand side of the identity into the right-hand side:\newlinecot2xcscx+1=cscx1\frac{\cot^{2}x}{\csc x+1} = \csc x - 1\newlineThis completes the proof.

More problems from Power rule