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Pluto's distance from the sun varies in a periodic way that can be 
m approximately by a trigonometric function.
Pluto's maximum distance from the sun (aphelion) is 7.4 billion kilo Its minimum distance from the sun (perihelion) is 4.4 billion kilomet Pluto last reached its perihelion in the year 1989 , and will next reac perihelion in 2237.
Find the formula of the trigonometric function that models Pluto's distance 
D from the sun (in billion 
km ) 
t years after 2000 . Define 
t function using radians.

D(t)=5.9+1.5 cos((2pi)/(248)(t+11))
How far will Pluto be from the sun in 2022 ? Round your answer, if necessary, to two decimal places.
billion km

Pluto's distance from the sun varies in a periodic way that can be modeled approximately by a trigonometric function.\newlinePluto's maximum distance from the sun (aphelion) is 7.47.4 billionbillion kmkm. Its minimum distance from the sun (perihelion) is 4.44.4 billionbillion kmkm. Pluto last reached its perihelion in the year 19891989, and will next reach perihelion in 22372237.\newlineFind the formula of the trigonometric function that models Pluto's distance DD from the sun (in billion km) tt years after 20002000. Define the function using radians.\newlineD(t)=5.9+1.5cos(2π248(t+11))D(t)=5.9+1.5 \cos\left(\frac{2\pi}{248}(t+11)\right)\newlineHow far will Pluto be from the sun in 20002000? Round your answer, if necessary, to two decimal places.\newlinebillionbillion kmkm

Full solution

Q. Pluto's distance from the sun varies in a periodic way that can be modeled approximately by a trigonometric function.\newlinePluto's maximum distance from the sun (aphelion) is 7.47.4 billionbillion kmkm. Its minimum distance from the sun (perihelion) is 4.44.4 billionbillion kmkm. Pluto last reached its perihelion in the year 19891989, and will next reach perihelion in 22372237.\newlineFind the formula of the trigonometric function that models Pluto's distance DD from the sun (in billion km) tt years after 20002000. Define the function using radians.\newlineD(t)=5.9+1.5cos(2π248(t+11))D(t)=5.9+1.5 \cos\left(\frac{2\pi}{248}(t+11)\right)\newlineHow far will Pluto be from the sun in 20002000? Round your answer, if necessary, to two decimal places.\newlinebillionbillion kmkm
  1. Given Function: We are given the function D(t)=5.9+1.5cos(2π248(t+11))D(t) = 5.9 + 1.5 \cos\left(\frac{2\pi}{248}(t + 11)\right). We need to find the distance DD from the sun in the year 20222022. To do this, we will substitute tt with the number of years after 20002000, which is 20222000=222022 - 2000 = 22.
  2. Substitute t=22t = 22: Substitute t=22t = 22 into the function D(t)D(t).D(22)=5.9+1.5cos(2π248(22+11))D(22) = 5.9 + 1.5 \cos\left(\frac{2\pi}{248}(22 + 11)\right)
  3. Calculate Argument: Calculate the argument of the cosine function.\newline(2π/248)(22+11)=(2π/248)(33)(2\pi/248)(22 + 11) = (2\pi/248)(33)
  4. Simplify Argument: Simplify the argument of the cosine function. \newline(2π248)(33)=66π248(\frac{2\pi}{248})(33) = \frac{66\pi}{248}
  5. Substitute Argument: Substitute the simplified argument back into the function D(t)D(t).\newlineD(22)=5.9+1.5cos(66π248)D(22) = 5.9 + 1.5 \cos(\frac{66\pi}{248})
  6. Calculate Cosine Value: Calculate the value of the cosine function using a calculator.\newlinecos(66π248)cos(0.83871)0.66920\cos\left(\frac{66\pi}{248}\right) \approx \cos(0.83871) \approx 0.66920
  7. Multiply and Add: Multiply the result of the cosine function by 1.51.5 and add it to 5.95.9. \newlineD(22)=5.9+1.5×0.66920D(22) = 5.9 + 1.5 \times 0.66920
  8. Perform Multiplication: Perform the multiplication.\newline1.5×0.66920=1.00381.5 \times 0.66920 = 1.0038
  9. Find Final Distance: Add the result to 5.95.9 to find the final distance.\newlineD(22)=5.9+1.0038D(22) = 5.9 + 1.0038
  10. Calculate Sum: Calculate the sum. D(22)=6.9038D(22) = 6.9038
  11. Round Answer: Round the answer to two decimal places as requested. D(22)6.90D(22) \approx 6.90 billion km

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