Q. Perform the multiplication a13(cotx+cscx)(cotx−cscx)
Identify Pattern: Identify the pattern in the expression.The given expression (cotx+cscx)(cotx−cscx) resembles the difference of squares pattern a2−b2=(a+b)(a−b).
Apply Formula: Apply the difference of squares formula.Using the pattern a2−b2=(a+b)(a−b), we can rewrite the expression as cot2x−csc2x.
Simplify Using Identities: Simplify the expression using trigonometric identities.We know that cot2x=sin2xcos2x and csc2x=sin2x1. Therefore, we can write cot2x−csc2x as sin2xcos2x−sin2x1.
Combine Over Common Denominator: Combine the terms over a common denominator.Since both terms have the same denominator sin2x, we can combine them to get sin2x(cos2x)−1.
Use Pythagorean Identity: Use the Pythagorean identity to simplify the numerator.The Pythagorean identity states that cos2x+sin2x=1. Therefore, cos2x−1=−(sin2x). We can substitute this into our expression to get −((sin2x)/(sin2x)).
Final Simplification: Simplify the expression.Since sin2x in the numerator and denominator are the same, they cancel out, leaving us with −1.