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Perform the addition 0150_{15}. \newline11+cosx+11cosx\frac{1}{1+\cos x}+\frac{1}{1-\cos x}

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Q. Perform the addition 0150_{15}. \newline11+cosx+11cosx\frac{1}{1+\cos x}+\frac{1}{1-\cos x}
  1. Write Expressions: Write down the expressions to be added.\newlineWe have two expressions: (1)/(1+cosx)(1)/(1+\cos x) and (1)/(1cosx)(1)/(1-\cos x).
  2. Find Common Denominator: Find a common denominator for the two expressions.\newlineThe common denominator for (1+cosx)(1+\cos x) and (1cosx)(1-\cos x) is (1+cosx)(1cosx)(1+\cos x)(1-\cos x).
  3. Rewrite with Common Denominator: Rewrite each fraction with the common denominator.\newlineThe first fraction becomes (1cosx(1+cosx)(1cosx))\left(\frac{1-\cos x}{(1+\cos x)(1-\cos x)}\right) and the second fraction becomes (1+cosx(1+cosx)(1cosx))\left(\frac{1+\cos x}{(1+\cos x)(1-\cos x)}\right).
  4. Add Fractions: Add the two fractions.\newlineNow that they have a common denominator, we can add the numerators: (1cosx)+(1+cosx)(1-\cos x) + (1+\cos x).
  5. Simplify Numerator: Simplify the numerator.\newlineWhen we add (1cosx)+(1+cosx)(1-\cos x) + (1+\cos x), the cosx\cos x terms cancel out, leaving us with 1+11 + 1, which equals 22.
  6. Write Combined Fraction: Write the combined fraction.\newlineThe combined fraction is now (2(1+cosx)(1cosx))(\frac{2}{(1+\cos x)(1-\cos x)}).
  7. Simplify Denominator: Simplify the denominator.\newlineWe recognize that (1+cosx)(1cosx)(1+\cos x)(1-\cos x) is the difference of squares, which simplifies to 1cos2x1 - \cos^2 x.
  8. Recognize Pythagorean Identity: Recognize the Pythagorean identity.\newlineWe know that cos2x+sin2x=1\cos^2 x + \sin^2 x = 1, so 1cos2x=sin2x1 - \cos^2 x = \sin^2 x.
  9. Substitute Identity: Substitute the identity into the denominator.\newlineThe denominator becomes sin2x\sin^2 x, so the fraction is now 2sin2x\frac{2}{\sin^2 x}.
  10. Write Final Form: Write the final simplified form.\newlineThe final simplified form of the sum is 2sin2x\frac{2}{\sin^2 x}.

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