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Paolo helped in the community garden for 2(3)/(4) hours this week. That was 1(5)/(6) equal-length shifts, because Paolo stopped early one day when it started to rain.
How long is a single shift?

◻ hours

Paolo helped in the community garden for 2342\frac{3}{4} hours this week. That was 1561\frac{5}{6} equal-length shifts, because Paolo stopped early one day when it started to rain. \newlineHow long is a single shift?\newline\square hours

Full solution

Q. Paolo helped in the community garden for 2342\frac{3}{4} hours this week. That was 1561\frac{5}{6} equal-length shifts, because Paolo stopped early one day when it started to rain. \newlineHow long is a single shift?\newline\square hours
  1. Convert to Improper Fraction: Paolo worked for 2(34)2\left(\frac{3}{4}\right) hours this week, which is 2+342 + \frac{3}{4} hours.\newlineConvert mixed number to improper fraction: 2(34)=(84+34)=1142\left(\frac{3}{4}\right) = \left(\frac{8}{4} + \frac{3}{4}\right) = \frac{11}{4} hours.
  2. Convert Shifts to Improper Fraction: He worked 1561\frac{5}{6} shifts, which is 1+561 + \frac{5}{6} shifts.\newlineConvert mixed number to improper fraction: 156=(66+56)=1161\frac{5}{6} = \left(\frac{6}{6} + \frac{5}{6}\right) = \frac{11}{6} shifts.
  3. Find Length of One Shift: To find the length of one shift, divide the total hours worked by the number of shifts.\newlineSo, (114)(\frac{11}{4}) hours ÷\div (116)(\frac{11}{6}) shifts = (114)×(611)(\frac{11}{4}) \times (\frac{6}{11}) shifts.
  4. Simplify Expression: Simplify the expression by canceling out the common factor of 1111.114×611=14×6=64\frac{11}{4} \times \frac{6}{11} = \frac{1}{4} \times 6 = \frac{6}{4}.
  5. Simplify to Lowest Terms: Simplify 64\frac{6}{4} to its lowest terms.\newline64=32\frac{6}{4} = \frac{3}{2} or 1121\frac{1}{2} hours per shift.

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