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p(x)=(x-0.95)(500-100 x) The equation models p, the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of x dollars each. What is the daily profit if the tacos are sold at $3 each? Choose 1 answer: (A) $410 (B) $600 (c) $820 (D) $2,460

p(x)=(x−0.95)(500−100x) p(x)=(x-0.95)(500-100 x) \newlineThe equation models p p , the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of x x dollars each. What is the daily profit if the tacos are sold at $3 \$ 3 each?\newlineChoose 11 answer:\newline(A) $410 \$ 410 \newline(B) $600 \$ 600 \newline(C) $820 \$ 820 \newline(D) $2,460 \$ 2,460

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Q. p(x)=(x−0.95)(500−100x) p(x)=(x-0.95)(500-100 x) \newlineThe equation models p p , the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of x x dollars each. What is the daily profit if the tacos are sold at $3 \$ 3 each?\newlineChoose 11 answer:\newline(A) $410 \$ 410 \newline(B) $600 \$ 600 \newline(C) $820 \$ 820 \newline(D) $2,460 \$ 2,460
  1. Substitute x into profit function: Substitute the value of x with $3\$3 into the profit function p(x)p(x).p(x)=(x−0.95)(500−100x)p(x) = (x - 0.95)(500 - 100x)p(3)=(3−0.95)(500−100⋅3)p(3) = (3 - 0.95)(500 - 100 \cdot 3)
  2. Perform calculations inside parentheses: Perform the calculations inside the parentheses.\newlinep33 = (2.05)(500−300)(2.05)(500 - 300)
  3. Continue with calculations: Continue with the calculations. p(3)=(2.05)(200)p(3) = (2.05)(200)
  4. Multiply numbers to find daily profit: Multiply the numbers to find the daily profit. p(3)=410p(3) = 410

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