P(t)=1,800(1.004)tThe function models P, the amount of money, in dollars, in Yara's savings account t years after she opened the account with an initial deposit of $1,800. How much money is in Yara's account 5 years after her initial deposit if she makes no deposits or withdraws in that time?Choose 1 answer:(A) $1,836.29(B) $1,873.31(C) $2,189.98(D) $9,036
Q. P(t)=1,800(1.004)tThe function models P, the amount of money, in dollars, in Yara's savings account t years after she opened the account with an initial deposit of $1,800. How much money is in Yara's account 5 years after her initial deposit if she makes no deposits or withdraws in that time?Choose 1 answer:(A) $1,836.29(B) $1,873.31(C) $2,189.98(D) $9,036
Given Function Calculation: Given the function P(t)=1,800(1.004)t, we need to calculate the amount of money in Yara's account after 5 years. We will substitute t with 5 in the function to find P(5).
Substitute t with 5: Perform the calculation for P(5) using the given function:P(5)=1,800(1.004)(5)
Evaluate Expression: Use a calculator or a computational tool to evaluate the expression: P(5)=1,800×(1.004)5
Multiply Result: After calculating the expression, we get: P(5)≈1,800×1.02020201
Round to Two Decimal Places: Now, multiply 1,800 by 1.02020201 to find the final amount:P(5)≈1,800×1.02020201≈1,836.36362
Compare with Answer Choices: Round the result to two decimal places to match the answer choices: P(5)≈$1,836.36
Compare with Answer Choices: Round the result to two decimal places to match the answer choices:P(5)≈$1,836.36Compare the result with the given answer choices:(A) $1,836.29(B) $1,873.31(C) $2,189.98(D) $9,036The closest answer to our calculation is (A) $1,836.29.
More problems from Identify equivalent linear expressions: word problems