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Over the next two days, Carroll Employment Agency is interviewing clients who wish to find jobs. On the first day, the agency plans to interview clients in groups of 1111. On the second day, the agency will interview clients in groups of 88. If the employment agency will interview the same number of clients on each day, what is the smallest number of clients that could be interviewed each day?\newline____\_\_\_\_ clients

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Q. Over the next two days, Carroll Employment Agency is interviewing clients who wish to find jobs. On the first day, the agency plans to interview clients in groups of 1111. On the second day, the agency will interview clients in groups of 88. If the employment agency will interview the same number of clients on each day, what is the smallest number of clients that could be interviewed each day?\newline____\_\_\_\_ clients
  1. Understand the problem: Step 11: Understand the problem.\newlineWe need to find the smallest number of clients that can be interviewed each day in groups of 1111 on the first day and 88 on the second day, without any leftover clients on either day.
  2. Identify mathematical approach: Step 22: Identify the mathematical approach.\newlineWe need to find the Least Common Multiple (LCM) of 1111 and 88, as this will give us the smallest number of clients that can be divided into groups of 1111 and 88 without any remainder.
  3. Calculate the LCM: Step 33: Calculate the LCM of 1111 and 88. First, list the multiples of 1111: 11,22,33,44,55,66,77,88,99,11011, 22, 33, 44, 55, 66, 77, 88, 99, 110\ldots Then, list the multiples of 88: 8,16,24,32,40,48,56,64,72,80,888, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88\ldots The smallest common multiple is 8888.

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