Oscar Murray - Opin... Untitled document -.. a. x^(2)-6x+8=0

Identify coefficients: Identify the coefficients of the quadratic equation x^2 - 6x + 8 = 0. Here, a = 1, b = -6, and c = 8. Use quadratic formula: Use the quadratic formula x = (-b ± sqrt(b^2 - 4ac)) / 2a to find the roots. Substitute a, b, and c into the formula. Calculate discriminant: Calculate the discriminant: b^2 - 4ac = (-6)^2 - 4*1*8 = 36 - 32 = 4. Substitute values: Substitute the values into the quadratic formula: x = (6 ± sqrt(4)) / 2*1 = (6 ± 2) / 2. Solve for x: Solve for x: x = (6 + 2) / 2 = 8 / 2 = 4 and x = (6 - 2) / 2 = 4 / 2 = 2.

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a. $x^{2}-6 x+8=0$

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Algebra 2

Find the sum of an arithmetic series

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Q. a.

x^{2}-6 x+8=0

Identify coefficients: Identify the coefficients of the quadratic equation $x^2 - 6x + 8 = 0$ . Here, $a = 1$ , $b = -6$ , and $c = 8$ .
Use quadratic formula: Use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ to find the roots. Substitute $a$ , $b$ , and $c$ into the formula.
Calculate discriminant: Calculate the discriminant: $b^2 - 4ac = (-6)^2 - 4\cdot1\cdot8 = 36 - 32 = 4$ .
Substitute values: Substitute the values into the quadratic formula: $x = \frac{6 \pm \sqrt{4}}{2 \cdot 1} = \frac{6 \pm 2}{2}$ .
Solve for x: Solve for x: $x = (6 + 2) / 2 = 8 / 2 = 4$ and $x = (6 - 2) / 2 = 4 / 2 = 2$ .