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One year, the population of a city was 376,000 . Several years later it was 338,400 .
Find the percent decrease.
Answer: ________
%

One year, the population of a city was 376376,000000 . Several years later it was 338338,400400 .\newlineFind the percent decrease.\newlineAnswer:________ % \%

Full solution

Q. One year, the population of a city was 376376,000000 . Several years later it was 338338,400400 .\newlineFind the percent decrease.\newlineAnswer:________ % \%
  1. Calculate Difference: Calculate the difference in population between the two years.\newlinePopulation in the first year: 376,000376,000\newlinePopulation in the several years later: 338,400338,400\newlineDifference in population: 376,000338,400376,000 - 338,400
  2. Perform Subtraction: Perform the subtraction to find the difference. 376,000338,400=37,600376,000 - 338,400 = 37,600
  3. Calculate Percentage Decrease: Calculate the percentage decrease in population.\newlinePercent decrease = (Difference in population/Population in the first year)×100%(\text{Difference in population} / \text{Population in the first year}) \times 100\%\newlinePercent decrease = (37,600/376,000)×100%(37,600 / 376,000) \times 100\%
  4. Perform Division and Multiplication: Perform the division and multiplication to find the percent decrease.\newlinePercent decrease = (37,600/376,000)×100%(37,600 / 376,000) \times 100\%\newlinePercent decrease = 0.1×100%0.1 \times 100\%\newlinePercent decrease = 10%10\%

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