One diagonal of a rhombus is decreasing at a rate of 7 centimeters per minute and the other diagonal of the rhombus is increasing at a rate of 10 centimeters per minute.At a certain instant, the decreasing diagonal is 4 centimeters and the increasing diagonal is 6 centimeters.What is the rate of change of the area of the rhombus at that instant (in square centimeters per minute)?Choose 1 answer:(A) −1(B) −16(C) 16(D) 1The area of a rhombus with diagonals d1 and d2 is 2d1d2.
Q. One diagonal of a rhombus is decreasing at a rate of 7 centimeters per minute and the other diagonal of the rhombus is increasing at a rate of 10 centimeters per minute.At a certain instant, the decreasing diagonal is 4 centimeters and the increasing diagonal is 6 centimeters.What is the rate of change of the area of the rhombus at that instant (in square centimeters per minute)?Choose 1 answer:(A) −1(B) −16(C) 16(D) 1The area of a rhombus with diagonals d1 and d2 is 2d1d2.
Rhombus Area Formula: The formula for the area of a rhombus is (d1×d2)/2, where d1 and d2 are the lengths of the diagonals.
Diagonal Lengths Given: Let's denote the decreasing diagonal as d1 and the increasing diagonal as d2. At the instant we are considering, d1=4cm and d2=6cm.
Rates of Change: The rate of change of d1 is −7cm/min (since it's decreasing) and the rate of change of d2 is 10cm/min (since it's increasing).
Rate of Change Formula: To find the rate of change of the area, we'll use the product rule for differentiation, which in this context is: (dtdA)=(d1⋅(dtdd2)+d2⋅(dtdd1))/2.
Calculate Rate of Change: Plugging in the values we have: (dtdA)=2(4cm×10cm/min+6cm×−7cm/min).
Perform Calculation: Now, let's do the calculation: (dtdA)=(240cm2/min−42cm2/min).
Simplify Result: Simplifying that, we get: (dtdA)=2−2cm2/min.
Final Rate of Change: Finally, we divide −2cm2/min by 2, which gives us (dtdA)=−1cm2/min.
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