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One day, a vendor sold 58 hot dogs and 84 bratwursts for a total of 
$268.30. The next day, the vendor sold 44 hot dogs and 92 bratwursts for a total of 
$271.40. What is the cost of one hot dog and the cost of one bratwurst? If the Winchester family buys 3 hot dogs and 2 bratwursts, how much will they pay?

One day, a vendor sold 5858 hot dogs and 8484 bratwursts for a total of $268.30 \$ 268.30 . The next day, the vendor sold 4444 hot dogs and 9292 bratwursts for a total of $271.40 \$ 271.40 . What is the cost of one hot dog and the cost of one bratwurst? If the Winchester family buys 33 hot dogs and 22 bratwursts, how much will they pay?

Full solution

Q. One day, a vendor sold 5858 hot dogs and 8484 bratwursts for a total of $268.30 \$ 268.30 . The next day, the vendor sold 4444 hot dogs and 9292 bratwursts for a total of $271.40 \$ 271.40 . What is the cost of one hot dog and the cost of one bratwurst? If the Winchester family buys 33 hot dogs and 22 bratwursts, how much will they pay?
  1. Equations setup: Let's denote the cost of one hot dog as HH dollars and the cost of one bratwurst as BB dollars. On the first day, the vendor sold 5858 hot dogs and 8484 bratwursts for a total of $268.30\$268.30. This gives us the equation:\newline58H+84B=268.3058H + 84B = 268.30
  2. Second day sales: On the second day, the vendor sold 4444 hot dogs and 9292 bratwursts for a total of $271.40\$271.40. This gives us the second equation:\newline44H+92B=271.4044H + 92B = 271.40
  3. Elimination method: We now have a system of two equations with two variables:\newline11) 58H+84B=268.3058H + 84B = 268.30\newline22) 44H+92B=271.4044H + 92B = 271.40\newlineWe can solve this system using the method of substitution or elimination. Let's use the elimination method to find the values of HH and BB.
  4. Multiplication for elimination: First, we'll multiply the first equation by 4444 and the second equation by 5858 to align the coefficients of HH for elimination:\newline(58H+84B)×44=268.30×44(58H + 84B) \times 44 = 268.30 \times 44\newline(44H+92B)×58=271.40×58(44H + 92B) \times 58 = 271.40 \times 58
  5. Subtracting equations: After performing the multiplication, we get:\newline2552H+3696B=11805.202552H + 3696B = 11805.20\newline2552H+5336B=15741.202552H + 5336B = 15741.20
  6. Solving for B: Now, we'll subtract the second equation from the first to eliminate H: \newlineegin{equation}(25522552H + 36963696B) - (25522552H + 53365336B) = 1180511805.2020 - 1574115741.2020\newlineegin{equation}
  7. Substitute back for H: This simplifies to:\newline1640B=3936-1640B = -3936
  8. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=3936/1640B = -3936 / -1640\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $2.40\$2.40.
  9. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=3936/1640B = -3936 / -1640\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $2.40\$2.40.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation:\newline58H+84(2.40)=268.3058H + 84(2.40) = 268.30
  10. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=3936/1640B = -3936 / -1640\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $2.40\$2.40.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation:\newline58H+84(2.40)=268.3058H + 84(2.40) = 268.30Calculating the value of 8484 times 2.402.40:\newlineBB00
  11. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=39361640B = \frac{-3936}{-1640}\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $2.40\$2.40.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation:\newline58H+84(2.40)=268.3058H + 84(2.40) = 268.30Calculating the value of 8484 times 2.402.40:\newline58H+201.60=268.3058H + 201.60 = 268.30Subtracting 201.60201.60 from both sides to solve for HH:\newline58H=268.30201.6058H = 268.30 - 201.60\newline58H=66.7058H = 66.70
  12. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=3936/1640B = -3936 / -1640\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $\$22.4040.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation:\newline58H+84(2.40)=268.3058H + 84(2.40) = 268.30Calculating the value of 8484 times 2.402.40:\newlineBB00Subtracting BB11 from both sides to solve for HH:\newlineBB33\newlineBB44Dividing both sides by BB55 to find the value of HH:\newlineBB77\newlineBB88\newlineSo, the cost of one hot dog is $\$11.1515.
  13. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get: B=39361640B = \frac{-3936}{-1640} B=2.40B = 2.40 So, the cost of one bratwurst is $2.40\$2.40.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation: 58H+84(2.40)=268.3058H + 84(2.40) = 268.30 Calculating the value of 84×2.4084 \times 2.40: 58H+201.60=268.3058H + 201.60 = 268.30 Subtracting 201.60201.60 from both sides to solve for HH: 58H=268.30201.6058H = 268.30 - 201.60 58H=66.7058H = 66.70 Dividing both sides by 5858 to find the value of HH: H=66.7058H = \frac{66.70}{58} H=1.15H = 1.15 So, the cost of one hot dog is BB00.Now that we have the cost of one hot dog (BB11) and one bratwurst (BB22), we can calculate the total cost for the Winchester family, who buys 33 hot dogs and 22 bratwursts: Total cost=3H+2B\text{Total cost} = 3H + 2B Total cost=3(1.15)+2(2.40)\text{Total cost} = 3(1.15) + 2(2.40)
  14. Calculating total cost: Dividing both sides by 1640-1640 to solve for BB, we get:\newlineB=39361640B = \frac{-3936}{-1640}\newlineB=2.40B = 2.40\newlineSo, the cost of one bratwurst is $2.40\$2.40.Now that we have the value of BB, we can substitute it back into one of the original equations to find HH. Let's use the first equation:\newline58H+84(2.40)=268.3058H + 84(2.40) = 268.30Calculating the value of 8484 times 2.402.40:\newline58H+201.60=268.3058H + 201.60 = 268.30Subtracting 201.60201.60 from both sides to solve for HH:\newline58H=268.30201.6058H = 268.30 - 201.60\newline58H=66.7058H = 66.70Dividing both sides by 5858 to find the value of HH:\newlineH=66.7058H = \frac{66.70}{58}\newlineH=1.15H = 1.15\newlineSo, the cost of one hot dog is BB11.Now that we have the cost of one hot dog (BB22) and one bratwurst (BB33), we can calculate the total cost for the Winchester family, who buys 33 hot dogs and 22 bratwursts:\newlineTotal cost=3H+2B\text{Total cost} = 3H + 2B\newlineTotal cost=3(1.15)+2(2.40)\text{Total cost} = 3(1.15) + 2(2.40)Calculating the total cost:\newlineB=2.40B = 2.4000\newlineB=2.40B = 2.4011\newlineThe Winchester family will pay BB44 for 33 hot dogs and 22 bratwursts.

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