On Sunday, 1/6 of the dogs seen in the park were on leashes. On Wednesday, 3/7 of the dogs in the same park were on leashes. Which day had a greater fraction of dogs on leashes?A)SundayB)Wednesday
Q. On Sunday, 1/6 of the dogs seen in the park were on leashes. On Wednesday, 3/7 of the dogs in the same park were on leashes. Which day had a greater fraction of dogs on leashes?A)SundayB)Wednesday
Understand fractions given: Understand the fractions given for each day.On Sunday, the fraction of dogs on leashes is (1)/(6).On Wednesday, the fraction of dogs on leashes is (3)/(7).We need to compare these two fractions to determine which is greater.
Compare fractions directly: Compare the two fractions directly.Since the denominators are different 6 and 7, we cannot directly compare the fractions by looking at the numerators. We need to find a common denominator or use another method to compare the fractions.
Use cross-multiplication: Use cross-multiplication to compare the fractions.Cross-multiply the fractions to compare their sizes without finding a common denominator. Multiply the numerator of the first fraction by the denominator of the second fraction and vice versa.(1)/(6) compared to (3)/(7) becomes:1×7=7 (for Sunday)3×6=18 (for Wednesday)
Determine greater product: Determine which product is greater.The product for Sunday is 7, and the product for Wednesday is 18. Since 18 is greater than 7, the fraction (3)/(7) is greater than (1)/(6).
Conclude greater fraction day: Conclude which day had a greater fraction of dogs on leashes. Since (3)/(7) is greater than (1)/(6), Wednesday had a greater fraction of dogs on leashes than Sunday.
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