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Nicole is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 
3.1% compounded quarterly. If Nicole would like to end up with 
$31,000 after 11 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Nicole is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 3.1% 3.1 \% compounded quarterly. If Nicole would like to end up with $31,000 \$ 31,000 after 1111 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Nicole is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 3.1% 3.1 \% compounded quarterly. If Nicole would like to end up with $31,000 \$ 31,000 after 1111 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $31,000\$31,000\newlineii (interest rate per period) = 3.1%3.1\% annual interest rate compounded quarterly, which is 3.1%4\frac{3.1\%}{4} per quarter\newlinenn (number of periods) = 1111 years * 44 quarters/year
  2. Convert Annual Interest Rate: Convert the annual interest rate to a quarterly interest rate. i=3.1% per year4 quarters per year=0.0314=0.00775i = \frac{3.1\% \text{ per year}}{4 \text{ quarters per year}} = \frac{0.031}{4} = 0.00775 per quarter
  3. Calculate Number of Periods: Calculate the number of periods nn.n=11 years×4 quarters/year=44 quartersn = 11 \text{ years} \times 4 \text{ quarters/year} = 44 \text{ quarters}
  4. Plug Values into Formula: Plug the values into the formula to solve for dd (the amount invested at the end of each period).A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)(\newline\)$31,000=d×((1+0.00775)4410.00775)\$31,000 = d \times \left(\frac{(1 + 0.00775)^{44} - 1}{0.00775}\right)
  5. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+0.00775)441(1 + 0.00775)^{44} - 1\newline= (1.00775)441(1.00775)^{44} - 1\newline= 1.41447711.414477 - 1\newline= 0.4144770.414477
  6. Divide by Interest Rate: Divide the result by the interest rate per period.\newline0.414477/0.00775=53.483610.414477 / 0.00775 = 53.48361
  7. Solve for d: Solve for d by dividing the future value of the account by the result from Step 66.\newlined=$31,00053.48361d = \frac{\$31,000}{53.48361}\newlined=579.346d = 579.346
  8. Round to Nearest Dollar: Round the result to the nearest dollar. d$579d \approx \$579

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