Factor each completely. x^(2)+x-12

Identify Factors: To factor the trinomial x^2 + x - 12, we need to find two numbers that multiply to -12 (the constant term) and add up to 1 (the coefficient of the x term).List Factor Pairs: We list the pairs of factors of -12: (-1, 12), (1, -12), (-2, 6), (2, -6), (-3, 4), and (3, -4).Find Pair Sum: We look for a pair of factors that add up to 1. The pair (3, -4) adds up to -1, and the pair (-3, 4) adds up to 1, which is the coefficient of the x term.Write as Binomials: We write the trinomial as a product of two binomials using the pair of factors we found: x^2 + x - 12 = (x - 3)(x + 4).

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Factor each completely. $\newline$ $x^{2}+x-12$

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Algebra 2

Factor sums and differences of cubes

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Q. Factor each completely.

\newline

x^{2}+x-12

Identify Factors: To factor the trinomial $x^2 + x - 12$ , we need to find two numbers that multiply to $-12$ (the constant term) and add up to $1$ (the coefficient of the $x$ term).
List Factor Pairs: We list the pairs of factors of $-12$ : $(-1, 12)$ , $(1, -12)$ , $(-2, 6)$ , $(2, -6)$ , $(-3, 4)$ , and $(3, -4)$ .
Find Pair Sum: We look for a pair of factors that add up to $1$ . The pair $(3, -4)$ adds up to $-1$ , and the pair $(-3, 4)$ adds up to $1$ , which is the coefficient of the $x$ term.
Write as Binomials: We write the trinomial as a product of two binomials using the pair of factors we found: $x^2 + x - 12 = (x - 3)(x + 4)$ .