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Mustafa is staring at a pizza spinning on a wheel in a glass case.
The pizza is cut into four even slices. The distance 
P(t) (in 
cm ) between the center of the tastiest looking slice and the door of the glass case as a function of time 
t (in seconds) can be modeled by a sinusoidal function of the form 
a*cos(b*t)+d.
At 
t=0, the center of the tastiest looking slice is farthest from the door, at a distance of 
30cm away. After 
2pi seconds, it is closest to the door, at a distance of 
10cm.
Find 
P(t).

t should be in radians.

P(t)=

Mustafa is staring at a pizza spinning on a wheel in a glass case.\newlineThe pizza is cut into four even slices. The distance P(t) P(t) (in cm \mathrm{cm} ) between the center of the tastiest looking slice and the door of the glass case as a function of time t t (in seconds) can be modeled by a sinusoidal function of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , the center of the tastiest looking slice is farthest from the door, at a distance of 30 cm 30 \mathrm{~cm} away. After 2π 2 \pi seconds, it is closest to the door, at a distance of 10 cm 10 \mathrm{~cm} .\newlineFind P(t) P(t) .\newlinet t should be in radians.\newlineP(t)= P(t)=

Full solution

Q. Mustafa is staring at a pizza spinning on a wheel in a glass case.\newlineThe pizza is cut into four even slices. The distance P(t) P(t) (in cm \mathrm{cm} ) between the center of the tastiest looking slice and the door of the glass case as a function of time t t (in seconds) can be modeled by a sinusoidal function of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , the center of the tastiest looking slice is farthest from the door, at a distance of 30 cm 30 \mathrm{~cm} away. After 2π 2 \pi seconds, it is closest to the door, at a distance of 10 cm 10 \mathrm{~cm} .\newlineFind P(t) P(t) .\newlinet t should be in radians.\newlineP(t)= P(t)=
  1. Given Distance Function: We are given that the distance function P(t)P(t) is a sinusoidal function of the form acos(bt)+da\cos(bt) + d. At t=0t=0, the distance is at its maximum, which is 3030 cm. This means that the vertical shift dd is 3030 cm, and the amplitude aa is the difference between the maximum and minimum distances.
  2. Calculate Amplitude: The maximum distance is 30cm30\,\text{cm} and the minimum distance is 10cm10\,\text{cm}. The amplitude aa is half the difference between the maximum and minimum distances.\newlineCalculation: a=(30cm10cm)/2=20cm/2=10cma = (30\,\text{cm} - 10\,\text{cm}) / 2 = 20\,\text{cm} / 2 = 10\,\text{cm}.
  3. Calculate Vertical Shift: Now we know that a=10cma = 10\,\text{cm}. The vertical shift dd is the average of the maximum and minimum distances.\newlineCalculation: d=(30cm+10cm)/2=40cm/2=20cmd = (30\,\text{cm} + 10\,\text{cm}) / 2 = 40\,\text{cm} / 2 = 20\,\text{cm}.
  4. Find Value of b: Next, we need to find the value of bb, which is related to the period of the function. We are told that after 2π2\pi seconds, the slice is closest to the door, which means that the period of the function is 2π2\pi seconds.\newlineCalculation: The period TT of a cosine function is given by T=2πbT = \frac{2\pi}{b}. Since T=2πT = 2\pi, we have 2πb=2π\frac{2\pi}{b} = 2\pi. Solving for bb gives us b=1b = 1.
  5. Final Sinusoidal Function: We have now determined all the parameters of the sinusoidal function: a=10cma = 10\, \text{cm}, b=1b = 1, and d=20cmd = 20\, \text{cm}. The function P(t)P(t) is therefore:\newlineP(t)=10cos(1t)+20.P(t) = 10\cos(1\cdot t) + 20.

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