Multiply. Write your answer in simplest form. -sqrt 5(-9 + sqrt 5) ______

Distribute -sqrt(5): Distribute -sqrt(5) to both terms inside the parentheses. -sqrt(5)(-9 + sqrt(5)) = -sqrt(5)*(-9) + -sqrt(5)*(sqrt(5))Calculate product of -sqrt(5) and -9: Calculate the product of -sqrt(5) and -9. -sqrt(5)*(-9) = 9*sqrt(5)Calculate product of -sqrt(5) and sqrt(5): Calculate the product of -sqrt(5) and sqrt(5). -sqrt(5)*sqrt(5) = -(sqrt(5))^2 Since the square root and the square cancel each other out, we have: -(sqrt(5))^2 = -5Combine results for final answer: Combine the results from the previous steps to get the final answer. 9*sqrt(5) - 5

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Multiply. Write your answer in simplest form. $\newline$ $-\sqrt{5}(-9 + \sqrt{5})$

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Algebra 2

Simplify radical expressions using the distributive property

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Q. Multiply. Write your answer in simplest form.

\newline

-\sqrt{5}(-9 + \sqrt{5})

Distribute $-\sqrt{5}$ : Distribute $-\sqrt{5}$ to both terms inside the parentheses.-\sqrt{$5$}(\(-9 + \sqrt{ $5$ }) = -\sqrt{ $5$ }( $-9$ ) + -\sqrt{ $5$ }(\sqrt{ $5$ })
Calculate product of $-\sqrt{5}$ and $-9$ : Calculate the product of $-\sqrt{5}$ and $-9$ . $-\sqrt{5}\cdot(-9) = 9\sqrt{5}$
Calculate product of $-\sqrt{5}$ and $\sqrt{5}$ : Calculate the product of $-\sqrt{5}$ and $\sqrt{5}$ . $\newline$ $-\sqrt{5}\times\sqrt{5}$ = $-\left(\sqrt{5}\right)^2$ $\newline$ Since the square root and the square cancel each other out, we have: $\newline$ $-\left(\sqrt{5}\right)^2 = -5$
Combine results for final answer: Combine the results from the previous steps to get the final answer. $9\sqrt{5} - 5$