Multiply. Write your answer in simplest form. -sqrt 3(2 + sqrt 3) ______

Distribute -sqrt(3): Distribute -sqrt(3) to both terms inside the parentheses. -sqrt(3)(2 + sqrt(3)) = -sqrt(3)*2 + -sqrt(3)*sqrt(3)Multiply -sqrt(3) by 2: Multiply -sqrt(3) by 2. -sqrt(3)*2 = -2sqrt(3)Multiply -sqrt(3) by sqrt(3): Multiply -sqrt(3) by sqrt(3). -sqrt(3)*sqrt(3) = -(sqrt(3))^2 = -3 (since the square root and the square cancel each other out)Combine results: Combine the results from Step 2 and Step 3. -2sqrt(3) - 3

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Multiply. Write your answer in simplest form. $\newline$ $-\sqrt{3}(2 + \sqrt{3})$

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Algebra 2

Simplify radical expressions using the distributive property

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Q. Multiply. Write your answer in simplest form.

\newline

-\sqrt{3}(2 + \sqrt{3})

Distribute $-\sqrt{3}$ : Distribute $-\sqrt{3}$ to both terms inside the parentheses. $-\sqrt{3}(2 + \sqrt{3}) = -\sqrt{3}\cdot 2 + -\sqrt{3}\cdot\sqrt{3}$
Multiply $-\sqrt{3}$ by $2$ : Multiply $-\sqrt{3}$ by $2$ . $\newline$ $-\sqrt{3}\times 2$ $\newline$ $= -2\sqrt{3}$
Multiply $-\sqrt{3}$ by $\sqrt{3}$ : Multiply $-\sqrt{3}$ by $\sqrt{3}$ . $\newline$ $-\sqrt{3}\times\sqrt{3}$ $\newline$ $= -(\sqrt{3})^2$ $\newline$ $= -3$ (since the square root and the square cancel each other out)
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ $-2\sqrt{3} - 3$