Multiply. Write your answer in simplest form. -sqrt 3(2 + sqrt 2) ______

Distribute -sqrt(3): Distribute -sqrt(3) to both terms inside the parentheses. -sqrt(3)(2 + sqrt(2)) =-sqrt(3)*2 - sqrt(3)*sqrt(2)Multiply -sqrt(3) by 2: Multiply -sqrt(3) by 2. -sqrt(3) * 2 = -2sqrt(3)Multiply -sqrt(3) by sqrt(2): Multiply -sqrt(3) by sqrt(2). -sqrt(3) * sqrt(2) = -sqrt(3 * 2) = -sqrt(6)Combine results: Combine the results from Step 2 and Step 3. -2sqrt(3) - sqrt(6)

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Multiply. Write your answer in simplest form. $\newline$ $-\sqrt{3}(2 + \sqrt{2})$

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Algebra 2

Simplify radical expressions using the distributive property

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Q. Multiply. Write your answer in simplest form.

\newline

-\sqrt{3}(2 + \sqrt{2})

Distribute $-\sqrt{3}$ : Distribute $-\sqrt{3}$ to both terms inside the parentheses. $-\sqrt{3}(2 + \sqrt{2}) =-\sqrt{3}\cdot 2 - \sqrt{3}\cdot \sqrt{2}$
Multiply $-\sqrt{3}$ by $2$ : Multiply $-\sqrt{3}$ by $2$ . $\newline$ $-\sqrt{3} \times 2$ $\newline$ $= -2\sqrt{3}$
Multiply $-\sqrt{3}$ by $\sqrt{2}$ : Multiply $-\sqrt{3}$ by $\sqrt{2}$ . $\newline$ $-\sqrt{3} \times \sqrt{2}$ $\newline$ = $-\sqrt{3 \times 2}$ $\newline$ = $-\sqrt{6}$
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ $-2\sqrt{3} - \sqrt{6}$