Multiply. Write your answer in simplest form. sqrt 3(-2 - sqrt 2) ______

Distribute sqrt(3): Distribute sqrt(3) to both terms inside the parentheses. sqrt(3)(-2 - sqrt(2)) = sqrt(3) * (-2) + sqrt(3) * (-sqrt(2))Multiply by -2: Multiply the square root of 3 by -2. sqrt(3) * (-2) = -2sqrt(3)Multiply by -sqrt(2): Multiply the square root of 3 by the negative square root of 2. sqrt(3) * (-sqrt(2)) = -sqrt(3 * 2) = -sqrt(6)Combine results: Combine the results from Step 2 and Step 3. -2sqrt(3) - sqrt(6)

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Multiply. Write your answer in simplest form. $\newline$ $\sqrt{3}(-2 - \sqrt{2})$

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Algebra 2

Simplify radical expressions using the distributive property

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Q. Multiply. Write your answer in simplest form.

\newline

\sqrt{3}(-2 - \sqrt{2})

Distribute $\sqrt{3}$ : Distribute $\sqrt{3}$ to both terms inside the parentheses. $\newline$ $\sqrt{3}(-2 - \sqrt{2})$ $\newline$ = $\sqrt{3} \times (-2) + \sqrt{3} \times (-\sqrt{2})$
Multiply by $-2$ : Multiply the square root of $3$ by $-2$ . $\sqrt{3} \times (-2) = -2\sqrt{3}$
Multiply by $-\sqrt{2}$ : Multiply the square root of $3$ by the negative square root of $2$ . $\sqrt{3} \times (-\sqrt{2}) = -\sqrt{3 \times 2} = -\sqrt{6}$
Combine results: Combine the results from Step $2$ and Step $3$ . $\newline$ $-2\sqrt{3} - \sqrt{6}$