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Multiply. Write your answer in simplest form.\newline3q+53q5×(2q+3)\frac{3q + 5}{3q - 5} \times (2q + 3)

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Q. Multiply. Write your answer in simplest form.\newline3q+53q5×(2q+3)\frac{3q + 5}{3q - 5} \times (2q + 3)
  1. Rewrite Multiplication Problem: Rewrite the multiplication problem to clearly show the two expressions that need to be multiplied.\newlineThe problem is (3q+5)/(3q5)×(2q+3)(3q + 5)/(3q - 5) \times (2q + 3).
  2. Identify Expression to Multiply: Identify the expression that will be multiplied.\newlineWe will multiply the fraction (3q+5)/(3q5)(3q + 5)/(3q - 5) by the binomial (2q+3)(2q + 3).
  3. Rewrite Binomial as Fraction: Rewrite the binomial as a fraction.\newlineThe binomial (2q+3)(2q + 3) can be written as a fraction by placing it over 11, so it becomes 2q+31\frac{2q + 3}{1}.
  4. Multiply Numerators and Denominators: Multiply the numerators and the denominators. The expression becomes (3q+5)×(2q+3)(3q5)×1\frac{(3q + 5) \times (2q + 3)}{(3q - 5) \times 1}.
  5. Perform Multiplication in Numerator: Perform the multiplication in the numerator.\newlineUse the distributive property (FOIL) to multiply the two binomials: (3q+5)×(2q+3)=3q×2q+3q×3+5×2q+5×3(3q + 5) \times (2q + 3) = 3q \times 2q + 3q \times 3 + 5 \times 2q + 5 \times 3.
  6. Calculate Products in Numerator: Calculate the products in the numerator.\newline3q×2q=6q23q \times 2q = 6q^2, 3q×3=9q3q \times 3 = 9q, 5×2q=10q5 \times 2q = 10q, and 5×3=155 \times 3 = 15.\newlineSo the numerator becomes 6q2+9q+10q+156q^2 + 9q + 10q + 15.
  7. Combine Like Terms in Numerator: Combine like terms in the numerator. 9q+10q=19q9q + 10q = 19q, so the numerator is now 6q2+19q+156q^2 + 19q + 15.
  8. Denominator Remains Unchanged: The denominator remains unchanged since it is being multiplied by 11. So the denominator is 3q53q - 5.
  9. Write Final Expression: Write the final expression.\newlineThe product of the two expressions is (6q2+19q+15)/(3q5)(6q^2 + 19q + 15) / (3q - 5).
  10. Check for Further Simplification: Check if the expression can be simplified further. The numerator and the denominator do not have any common factors other than 11, so the expression is already in its simplest form.

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