Multiply. Write your answer in simplest form. 2v/3 * (v - 3) ______

Rewrite multiplication: Rewrite the multiplication of the fraction and the binomial. So, (2v/3) * (v - 3) = (2v/3) * v/1 - (2v/3) * 3/1.Multiply first term: Multiply the numerators and denominators separately for the first term. So, (2v/3) * v/1 = (2v * v)/(3 * 1) = 2v^2/3.Multiply second term: Multiply the numerators and denominators separately for the second term. So, (2v/3) * 3/1 = (2v * 3)/(3 * 1) = 6v/3.Simplify second term: Simplify the second term. Since 6v/3 is divisible by 3, we can simplify it to 2v.Combine terms: Combine the two terms. So, 2v^2/3 - 2v.Final simplification: Since there are no like terms to combine further and no common factors to simplify, the expression is already in its simplest form.

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Multiply. Write your answer in simplest form. $\newline$ $\frac{2v}{3} \times (v - 3)$

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Algebra 1

Multiply and divide rational expressions

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Q. Multiply. Write your answer in simplest form.

\newline

\frac{2v}{3} \times (v - 3)

Rewrite multiplication: Rewrite the multiplication of the fraction and the binomial. So, $(\frac{2v}{3}) \times (v - 3) = (\frac{2v}{3}) \times \frac{v}{1} - (\frac{2v}{3}) \times \frac{3}{1}$ .
Multiply first term: Multiply the numerators and denominators separately for the first term. So, $(\frac{2v}{3}) \times \frac{v}{1} = \frac{2v \times v}{3 \times 1} = \frac{2v^2}{3}$ .
Multiply second term: Multiply the numerators and denominators separately for the second term. So, $(\frac{2v}{3}) \times \frac{3}{1} = \frac{2v \times 3}{3 \times 1} = \frac{6v}{3}$ .
Simplify second term: Simplify the second term. Since $\frac{6v}{3}$ is divisible by $3$ , we can simplify it to $2v$ .
Combine terms: Combine the two terms. So, $\frac{2v^2}{3} - 2v$ .
Final simplification: Since there are no like terms to combine further and no common factors to simplify, the expression is already in its simplest form.