Multiply. Write your answer in simplest form. 2q + 1/q^2 * 9q^2 - 6q + 1/3q + 2 ______

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Identify Expressions: Identify the expressions to be multiplied. We have two fractions to multiply: (2q + 1)/q^2 and (9q^2 - 6q + 1)/(3q + 2).Multiply Numerators and Denominators: Multiply the numerators and the denominators. The product of the two fractions is (2q + 1)(9q^2 - 6q + 1) / (q^2)(3q + 2).Perform Multiplication in Numerator: Perform the multiplication in the numerator. We need to multiply the two binomials (2q + 1) and (9q^2 - 6q + 1) using the distributive property (FOIL method). (2q + 1)(9q^2 - 6q + 1) = 2q(9q^2) + 2q(-6q) + 2q(1) + 1(9q^2) - 1(6q) + 1(1) = 18q^3 - 12q^2 + 2q + 9q^2 - 6q + 1 = 18q^3 - 3q^2 - 4q + 1Write Product as Single Fraction: Write the product as a single fraction. Now we have the numerator, we can write the product as a single fraction: (18q^3 - 3q^2 - 4q + 1) / (q^2)(3q + 2)Simplify Fraction: Simplify the fraction if possible. Looking at the numerator and the denominator, there are no common factors that can be canceled out. Therefore, the fraction is already in its simplest form.

Multiply. Write your answer in simplest form. $\newline$ $\frac{2q + 1}{q^2} \times \frac{9q^2 - 6q + 1}{3q + 2}$

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Multiply. Write your answer in simplest form. $\newline$ $\frac{2q + 1}{q^2} \times \frac{9q^2 - 6q + 1}{3q + 2}$