Multiply. Write your answer (3g-2)/(g^(2)-1)*(g+1)

Rewrite multiplication: Rewrite the multiplication of the two fractions. So, (3g-2)/(g^2-1) * (g+1) = (3g-2) * (g+1) / (g^2-1).Factor denominator: Factor the denominator g^2-1 to (g-1)(g+1).Cancel common factors: Cancel out the common factors in the numerator and the denominator. The (g+1) in the numerator and denominator cancel each other out. So, (3g-2) * (g+1) / (g^2-1) becomes (3g-2) / (g-1).Final answer: The final answer is (3g-2) / (g-1).

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Multiply. Write your answer

(3g-2)/(g^(2)-1)*(g+1)

Multiply. Write your answer $\newline$ $\frac{3 g-2}{g^{2}-1} \cdot(g+1)$

View step-by-step help

Home

Math Problems

Algebra 1

Multiply and divide rational expressions

Full solution

Q. Multiply. Write your answer

\newline

\frac{3 g-2}{g^{2}-1} \cdot(g+1)

Rewrite multiplication: Rewrite the multiplication of the two fractions. So, $(3g-2)/(g^2-1) \times (g+1) = (3g-2) \times (g+1) / (g^2-1)$ .
Factor denominator: Factor the denominator $g^2-1$ to $(g-1)(g+1)$ .
Cancel common factors: Cancel out the common factors in the numerator and the denominator. The $(g+1)$ in the numerator and denominator cancel each other out. So, $(3g-2) \times (g+1) / (g^2-1)$ becomes $(3g-2) / (g-1)$ .
Final answer: The final answer is $(3g-2) / (g-1)$ .