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Multiply. Simplify your answer. \newline10j29j2×15hj\frac{10j^2}{9j^2} \times 15hj

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Q. Multiply. Simplify your answer. \newline10j29j2×15hj\frac{10j^2}{9j^2} \times 15hj
  1. Identify multiplication: Identify the multiplication of the two fractions. We have the fraction 10j29j2\frac{10j^2}{9j^2} and we are multiplying it by 15hj15hj. This can be written as (10j29j2)(15hj1)\left(\frac{10j^2}{9j^2}\right) * \left(\frac{15hj}{1}\right).
  2. Cancel common factors: Cancel out common factors in the numerator and the denominator before multiplying. In this case, we can cancel out the j2j^2 terms.\newlineSo, (10j29j2)×(15hj1)(\frac{10j^2}{9j^2}) \times (\frac{15hj}{1}) becomes (109)×(15hj1)(\frac{10}{9}) \times (\frac{15hj}{1}) because j2/j2j^2/j^2 is 11.
  3. Multiply numerators and denominators: Multiply the numerators and then the denominators. The numerator is 10×15hj10 \times 15hj, and the denominator is 9×19 \times 1.\newlineSo, (109)×(15hj1)=10×15hj9×1.(\frac{10}{9}) \times (\frac{15hj}{1}) = \frac{10 \times 15hj}{9 \times 1}.
  4. Perform multiplication: Perform the multiplication in the numerator and the denominator.\newlineThe numerator is 10×15hj10 \times 15hj which is 150hj150hj, and the denominator is 9×19 \times 1 which is 99.\newlineSo, (10×15hj)/(9×1)=150hj/9(10 \times 15hj) / (9 \times 1) = 150hj / 9.
  5. Simplify fraction: Simplify the fraction if possible. In this case, we can divide both the numerator and the denominator by 33 to simplify the fraction. 150hj9=(150/3)hj(9/3)=50hj3\frac{150hj}{9} = \frac{(150/3)hj}{(9/3)} = \frac{50hj}{3}.

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