Mr. Free's science class measures rain for two months. In the first month, there was (2)/(5) of an inch of rain. In the second month, there was (1)/(5) of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach (4)/(5) of an inch for all three months?

Add Rainfall Calculation: Step 1: Add the rainfall from the first two months. Calculation: (2/5) inch + (1/5) inch = (3/5) inch.Calculate Additional Rain Needed: Step 2: Determine how much more rain is needed in the third month to reach (4/5) inch total. Calculation: (4/5) inch - (3/5) inch = (1/5) inch.

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Mr. Free's science class measures rain for two months. In the first month, there was
(2)/(5) of an inch of rain. In the second month, there was
(1)/(5) of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach
(4)/(5) of an inch for all three months?

Mr. Free's science class measures rain for two months. In the first month, there was $\frac{2}{5}$ of an inch of rain. In the second month, there was $\frac{1}{5}$ of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach $\frac{4}{5}$ of an inch for all three months?

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Grade 6

Evaluate variable expressions: word problems

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Q. Mr. Free's science class measures rain for two months. In the first month, there was

\frac{2}{5}

of an inch of rain. In the second month, there was

\frac{1}{5}

of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach

\frac{4}{5}

of an inch for all three months?

Add Rainfall Calculation: Step $1$ : Add the rainfall from the first two months. $\newline$ Calculation: $(\frac{2}{5})$ inch + $(\frac{1}{5})$ inch = $(\frac{3}{5})$ inch.
Calculate Additional Rain Needed: Step $2$ : Determine how much more rain is needed in the third month to reach $(\frac{4}{5})$ inch total. $\newline$ Calculation: $(\frac{4}{5})$ inch - $(\frac{3}{5})$ inch = $(\frac{1}{5})$ inch.