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Mason has some nickels and some dimes. He has a minimum of coins worth at most combined. If Mason has dimes, determine the maximum number of nickels that he could have.Answer:
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Q. Mason has some nickels and some dimes. He has a minimum of coins worth at most combined. If Mason has dimes, determine the maximum number of nickels that he could have.Answer:
- Calculate Dime Value: First, let's determine the value of the dimes Mason has.Since each dime is worth , dimes are worth .Calculation:
- Calculate Remaining Amount: Now, let's calculate the remaining amount that can be allocated to nickels. Mason has at most , and he already has in dimes. Calculation:
- Calculate Maximum Nickels: Each nickel is worth \$\(0\).\(05\). To find the maximum number of nickels Mason can have, we divide the remaining amount by the value of one nickel.\(\newline\)Calculation: \$\(0\).\(70\) \div \$\(0\).\(05\) = \(14\) nickels
- Ensure Total Coins: We must ensure that the total number of coins is at least \(15\). Mason already has \(3\) dimes, so adding \(14\) nickels would give him a total of \(17\) coins.\(\newline\)Calculation: \(3\) dimes \(+\) \(14\) nickels \(=\) \(17\) coins
- Final Conclusion: Since \(17\) coins are more than the minimum of \(15\) coins required, Mason can indeed have \(14\) nickels along with his \(3\) dimes.
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