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Mariam is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 
5% compounded quarterly. If Mariam would like to end up with 
$8,000 after 3 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Mariam is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 5% 5 \% compounded quarterly. If Mariam would like to end up with $8,000 \$ 8,000 after 33 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Mariam is saving money and plans on making quarterly contributions into an account earning an annual interest rate of 5% 5 \% compounded quarterly. If Mariam would like to end up with $8,000 \$ 8,000 after 33 years, how much does she need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineFuture value of the account, A=$(8,000)A = \$(8,000)\newlineAnnual interest rate =5%= 5\%\newlineNumber of years =3= 3\newlineSince the interest is compounded quarterly, there are 44 periods per year.\newlineTherefore, the number of periods, n=3n = 3 years ×4\times 4 quarters/year =12= 12 quarters\newlineThe interest rate per period, i=(5%i = (5\% annual interest rate) /4/ 4 quarters =1.25%= 1.25\% per quarter or =5%= 5\%00 in decimal form.
  2. Substitute Values into Formula: Substitute the given values into the formula to solve for dd, the amount invested at the end of each period.\newlineWe have the formula A=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^{n} - 1\right) / i\newlineSubstituting the values, we get:\newline$8,000=d×((1+0.0125)121)/0.0125\$8,000 = d \times \left(\left(1 + 0.0125\right)^{12} - 1\right) / 0.0125
  3. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newlineCalculate (1+i)n(1 + i)^n:\newline(1+0.0125)12(1 + 0.0125)^{12}
  4. Perform Exponentiation: Perform the exponentiation.\newline(1+0.0125)121.160(1 + 0.0125)^{12} \approx 1.160
  5. Continue Calculation of Formula: Continue with the calculation of the formula.$8,000=d×(1.16010.0125)\$8,000 = d \times \left(\frac{1.160 - 1}{0.0125}\right)
  6. Calculate Numerator of Fraction: Calculate the numerator of the fraction.\newline1.1601=0.1601.160 - 1 = 0.160
  7. Calculate Denominator of Fraction: Calculate the denominator of the fraction.\newlineNow we have:\newline$8,000=d×(0.160/0.0125)\$8,000 = d \times (0.160 / 0.0125)
  8. Perform Division: Perform the division to solve for dd.$8,000=d×(12.8)\$8,000 = d \times (12.8)
  9. Isolate d: Isolate d to solve for the quarterly contribution. d=$8,00012.8d = \frac{\$8,000}{12.8}
  10. Calculate Value of d: Calculate the value of d.\newlined$625d \approx \$625
  11. Round Value of d: Round the value of dd to the nearest dollar. Mariam needs to contribute approximately $625\$625 every quarter.

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