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Mackenzie deposits 
$690 every month into an account earning a monthly interest rate of 
0.25%. How much would she have in the account after 13 months, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Mackenzie deposits $690 \$ 690 every month into an account earning a monthly interest rate of 0.25% 0.25 \% . How much would she have in the account after 1313 months, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Mackenzie deposits $690 \$ 690 every month into an account earning a monthly interest rate of 0.25% 0.25 \% . How much would she have in the account after 1313 months, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlinedd (the amount invested at the end of each period) = $690\$690\newlineii (the interest rate per period) = 0.25%0.25\% or 0.00250.0025 in decimal form\newlinenn (the number of periods) = 1313 months\newlineWe will use these values in the formula A=d((1+i)n1i)A=d\left(\frac{(1+i)^{n}-1}{i}\right) to find AA, the future value of the account.
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal.\newline0.25%=0.25100=0.00250.25\% = \frac{0.25}{100} = 0.0025\newlineThis is the value of ii that we will use in the formula.
  3. Substitute Values into Formula: Substitute the values into the formula.\newlineA=690×((1+0.0025)131)/0.0025A = 690 \times \left(\left(1 + 0.0025\right)^{13} - 1\right) / 0.0025\newlineNow we will calculate the value inside the parentheses first.
  4. Calculate (1+i)n(1 + i)^{n}: Calculate the value of (1+i)n(1 + i)^{n}.(1+0.0025)13=1.002513(1 + 0.0025)^{13} = 1.0025^{13} We will use a calculator to find this value.
  5. Calculate 1.0025131.0025^{13}: Calculate the value of 1.0025131.0025^{13}. \newline1.0025131.0331.0025^{13} \approx 1.033\newlineThis is the value we will use in the next step of our calculation.
  6. Calculate ((1+i)n1)((1 + i)^{n} - 1): Calculate the value of ((1+i)n1)((1 + i)^{n} - 1). \newline1.0331=0.0331.033 - 1 = 0.033\newlineThis is the value we will use in the next step of our calculation.
  7. Calculate (((1+i)n1)/i)(((1 + i)^{n} - 1) / i): Calculate the value of (((1+i)n1)/i)(((1 + i)^{n} - 1) / i). \newline0.033/0.0025=13.20.033 / 0.0025 = 13.2\newlineThis is the value we will use in the next step of our calculation.
  8. Calculate Future Value of Account: Calculate the future value of the account, AA.A=690×13.2A = 690 \times 13.2Now we will multiply to find the future value of the account.
  9. Calculate Final Value of A: Calculate the final value of A.\newlineA=690×13.29108A = 690 \times 13.2 \approx 9108\newlineWe round to the nearest dollar as instructed in the problem.

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