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M=8(4.5C)M=8(4.5-C)\newlineThe magnetic field, MM, in microtesla, at the center of a loop with a current of CC milliamps clockwise is given by the equation. By how many microteslas does the magnetic field change for a 11 milliamp increase in the current?\newlineChoose 11 answer:\newline(A) 8-8\newline(B) 4.5-4.5\newline(C) 2828\newline(D) 3636

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Q. M=8(4.5C)M=8(4.5-C)\newlineThe magnetic field, MM, in microtesla, at the center of a loop with a current of CC milliamps clockwise is given by the equation. By how many microteslas does the magnetic field change for a 11 milliamp increase in the current?\newlineChoose 11 answer:\newline(A) 8-8\newline(B) 4.5-4.5\newline(C) 2828\newline(D) 3636
  1. Given Equation: We are given the equation M=8(4.5C)M = 8(4.5 - C), where MM is the magnetic field in microteslas and CC is the current in milliamps. We need to find out how much MM changes when CC increases by 11 milliamp.
  2. Calculate M for C: Let's first calculate the magnetic field MM for a current CC. Then we will calculate the magnetic field MM for a current C+1C + 1. The difference between these two values will give us the change in the magnetic field for a 11 milliamp increase in the current.
  3. Calculate MM for C+1C + 1: For the current CC, the magnetic field is M=8(4.5C)M = 8(4.5 - C).
  4. Find Change in M: For the current C+1C + 1, the magnetic field is M=8(4.5(C+1))=8(4.5C1)=8(3.5C)M' = 8(4.5 - (C + 1)) = 8(4.5 - C - 1) = 8(3.5 - C).
  5. Simplify Expression: Now we find the change in the magnetic field, which is ΔM=MM\Delta M = M' - M. Substituting the expressions for MM' and MM, we get ΔM=8(3.5C)8(4.5C)\Delta M = 8(3.5 - C) - 8(4.5 - C).
  6. Calculate ΔM\Delta M: Simplifying the expression for ΔM\Delta M, we get ΔM=8(3.5C)8(4.5C)=8×3.58×C(8×4.58×C)\Delta M = 8(3.5 - C) - 8(4.5 - C) = 8 \times 3.5 - 8 \times C - (8 \times 4.5 - 8 \times C).
  7. Calculate ΔM\Delta M: Simplifying the expression for ΔM\Delta M, we get ΔM=8(3.5C)8(4.5C)=8×3.58×C(8×4.58×C)\Delta M = 8(3.5 - C) - 8(4.5 - C) = 8 \times 3.5 - 8 \times C - (8 \times 4.5 - 8 \times C).Notice that the 8×C-8 \times C and +8×C+8 \times C cancel each other out, so we are left with ΔM=8×3.58×4.5\Delta M = 8 \times 3.5 - 8 \times 4.5.
  8. Calculate ΔM\Delta M: Simplifying the expression for ΔM\Delta M, we get ΔM=8(3.5C)8(4.5C)=8×3.58×C(8×4.58×C)\Delta M = 8(3.5 - C) - 8(4.5 - C) = 8 \times 3.5 - 8 \times C - (8 \times 4.5 - 8 \times C).Notice that the 8×C-8 \times C and +8×C+8 \times C cancel each other out, so we are left with ΔM=8×3.58×4.5\Delta M = 8 \times 3.5 - 8 \times 4.5.Calculating the values, we get ΔM=2836=8\Delta M = 28 - 36 = -8 microteslas.

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