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m=14(11-t) The mass, m, in grams, of a piece of marble after being in a rock tumbler for t minutes is given by the equation. After how many minutes in the rock tumbler does the piece of marble disintegrate by reaching a mass of 0 grams? Choose 1 answer: (A) 3 (B) 11 (C) 14 (D) 154

m=14(11−t) m=14(11-t) \newlineThe mass, m m , in grams, of a piece of marble after being in a rock tumbler for t t minutes is given by the equation. After how many minutes in the rock tumbler does the piece of marble disintegrate by reaching a mass of 00 grams?\newlineChoose 11 answer:\newline(A) 33\newline(B) 1111\newline(C) 1414\newline(D) 154 \mathbf{1 5 4}

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Q. m=14(11−t) m=14(11-t) \newlineThe mass, m m , in grams, of a piece of marble after being in a rock tumbler for t t minutes is given by the equation. After how many minutes in the rock tumbler does the piece of marble disintegrate by reaching a mass of 00 grams?\newlineChoose 11 answer:\newline(A) 33\newline(B) 1111\newline(C) 1414\newline(D) 154 \mathbf{1 5 4}
  1. Understand the equation: Understand the equation given.\newlineThe equation m=14(11−t)m = 14(11 - t) represents the mass mm of a piece of marble after tt minutes in a rock tumbler. We need to find the value of tt when the mass mm becomes 00 grams.
  2. Set equation to 00: Set the equation equal to 00 to find when the marble disintegrates.\newline0=14(11−t)0 = 14(11 - t)
  3. Divide and isolate term: Divide both sides of the equation by 1414 to isolate the term (11−t)(11 - t). \newline014=(11−t)\frac{0}{14} = (11 - t)
  4. Simplify left side: Simplify the left side of the equation. 0=11−t0 = 11 - t
  5. Solve for t: Solve for t by adding tt to both sides and subtracting 00 from both sides.\newlinet=11−0t = 11 - 0
  6. Simplify right side: Simplify the right side of the equation to find the value of tt.t=11t = 11

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