Look at this set of ordered pairs: (16, 16) (16, 9) (12, 15) Is this relation a function? Choices: (A)yes (B)no

Understand function definition: Step 1: Understand the definition of a function. A relation is a function if each input (x-value) has exactly one output (y-value). Examine ordered pairs: Step 2: Examine the given ordered pairs for repeated x-values with different y-values. The pairs are (16, 16), (16, 9), and (12, 15). Identify repeated x-values: Step 3: Notice that the x-value 16 appears with two different y-values: 16 and 9. This means that the same input gives different outputs. Violation of function definition: Step 4: Since the same x-value (16) maps to more than one y-value, this violates the definition of a function. Therefore, the relation is not a function.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Look at this set of ordered pairs: $\newline$ $(16, 16)$ $\newline$ $(16, 9)$ $\newline$ $(12, 15)$ $\newline$ Is this relation a function? $\newline$ Choices: $\newline$ (A) yes $\newline$ (B) no

View step-by-step help

Full solution

Q. Look at this set of ordered pairs:

\newline

(16, 16)

\newline

(16, 9)

\newline

(12, 15)

\newline

Is this relation a function?

\newline

Choices:

\newline

(A) yes

\newline

(B) no

Understand function definition: Step $1$ : Understand the definition of a function. A relation is a function if each input ( $x$ -value) has exactly one output ( $y$ -value).
Examine ordered pairs: Step $2$ : Examine the given ordered pairs for repeated $x$ -values with different $y$ -values. The pairs are $(16, 16)$ , $(16, 9)$ , and $(12, 15)$ .
Identify repeated $x$ -values: Step $3$ : Notice that the $x$ -value $16$ appears with two different $y$ -values: $16$ and $9$ . This means that the same input gives different outputs.
Violation of function definition: Step $4$ : Since the same $x$ -value ( $16$ ) maps to more than one $y$ -value, this violates the definition of a function. Therefore, the relation is not a function.