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Let’s check out your problem:
log
1
5
5
=
\log _{\frac{1}{5}} 5=
lo
g
5
1
5
=
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Math Problems
Grade 8
Add and subtract rational numbers
Full solution
Q.
log
1
5
5
=
\log _{\frac{1}{5}} 5=
lo
g
5
1
5
=
Identify Base and Argument:
Identify the base of the logarithm and the argument. The base is
(
1
5
)
(\frac{1}{5})
(
5
1
)
and the argument is
5
5
5
.
Recall Logarithm Definition:
Recall the definition of a logarithm:
log
base
(
argument
)
=
exponent
\log_{\text{base}}(\text{argument}) = \text{exponent}
lo
g
base
(
argument
)
=
exponent
means that
base
exponent
=
argument
\text{base}^{\text{exponent}} = \text{argument}
base
exponent
=
argument
.
Determine Exponent:
Determine the exponent that makes
(
1
5
)
(\frac{1}{5})
(
5
1
)
raised to that power equal to
5
5
5
. Since
(
1
5
)
−
1
=
5
(\frac{1}{5})^{-1} = 5
(
5
1
)
−
1
=
5
, the exponent we are looking for is
−
1
-1
−
1
.
Conclude Solution:
Conclude that
log
(
1
5
)
5
=
−
1
\log_{\left(\frac{1}{5}\right)}5 = -1
lo
g
(
5
1
)
5
=
−
1
because
(
1
5
)
−
1
=
5
\left(\frac{1}{5}\right)^{-1} = 5
(
5
1
)
−
1
=
5
.
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